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Studentka2010 [4]
3 years ago
10

2

Mathematics
1 answer:
Crazy boy [7]3 years ago
7 0

Answer:

  Each point (or pair in a proportional relationship) must share the same difference

Step-by-step explanation:

The graph of a proportional relation is a straight line through the origin. Such a line has the same ratio of y/x everywhere.

A relation in which the difference is constant will be a straight line, but it won't be through the origin. Such a relation is not proportional.

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Step-by-step explanation:

Q1

7x people=14x^2/15

1 person= (14x^2/15)÷7x

// =(7x^2/15)÷x

Each person will recieve= (7x^2/15)÷x

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3 years ago
According to Thomson Financial, last year the majority of companies reporting profits had beaten estimates. A sample of 162 comp
vova2212 [387]

Answer:

0.1790

0.0738 , 0.5800, 0.7040

354

Step-by-step explanation:

a. Given:  

n = 162

x = 29

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:  

p =  x/n

  = 29/162

  = 0.1790

b. Given:  

n=162

x = 110

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:  

p =  x/n

  =110/162

  =0.6790

For confidence level 1 –\alpha = 0.95, determine z_\alpha/2 = z_0.025 using table 1 (look up 0.025 in the table, the z-score is then the found z-score with opposite sign):  

z_\alpha/2 = 1.96  

The margin of error is then:

E =  z_\alpha/2*√p(1-p)/n =1.96* √0.6790(1-0.6790)/162 =0.0738

The boundaries of the confidence interval are then:  

p-z_\alpha/2*√p(1-p)/n = 0.6790-1.645√ 0.6790(1- 0.6790)/162 = 0.5800

p+z_\alpha/2*√p(1-p)/n = 0.6790+1.645√ 0.6790(1- 0.6790)/162 = 0.7040

c. Given:  

n = 162

x = 110

c = 95%

The point estimate of the population proportion is the sample proportion. The sample proportion is the number of successes divided by the sample size:  

p =x/n

  =0.6790

Formula sample size:

p known: n = [z_\alpha/2 ]^2*pq/E^2

                   = [z_\alpha/2 ]^2*p(1-p)/E^2

                n = [z_\alpha/2 ]^2*0.25/E^2

For confidence level 1 –\alpha= 0.95, determine z_\alpha/2 = z_o.025 using table 1 (look up 0.025 in the table, the z-score is then the found z-score with opposite sign):  

z_\alpha/2  = 1.96

p is known, then the sample size is (round up!):

n =[z_\alpha/2 ]^2*p(1-p)/E^2

  = 354

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Step-by-step explanation:

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