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Sav [38]
2 years ago
6

To shift the graph of an equation a certain number of units _____, you need to subtract that number from the functions equation

Mathematics
2 answers:
vredina [299]2 years ago
8 0

Answer: D, because A function can be shift vertically up or down by adding some positive or negative constant.

FromTheMoon [43]2 years ago
3 0

Answer:

The correct option is A) Down.

Step-by-step explanation:

A function can be shift vertically up or down by adding some positive or negative constant.

For example:

Consider the figure 1:

The function g(x)=f(x)+k shifted up by <em>k</em> unit. (where <em>k</em> is 1 unit)

Now consider the figure 2:

The function g(x)=f(x)-k shifted down by <em>k</em> unit. (where <em>k</em> is 1 unit)

Which means to shift the graph of an equation certain number of units up, we need to add that number from the functions equation.

Similarly, to shift the graph of an equation certain number of units down, we need to subtract that number from the functions equation.

Therefore, the correct option is A) Down.

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Name the property the equation illustrates.
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A parabola has two x intercepts at (-2 , 0) and (3 , 0) and passes through the point (5 , 10). Find the equation of this parabol
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What is the value of x? pleeaseee answer!!!
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5 0
3 years ago
Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((
Alexus [3.1K]

Answer:

q^{-30}

Step-by-step explanation:

Given the expression:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}

First, we open the outer brackets

=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}

Therefore:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}=q^{-30

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