Given:
Sides of triangles in the options.
To find:
Which could NOT be the lengths of the sides of a triangle.
Solution:
Condition for triangle:
Sum of two smaller sides of a triangle must be greater than the longest side.
In option A,
![5+5=10>5](https://tex.z-dn.net/?f=5%2B5%3D10%3E5)
Sides 5 in, 5 in, 5 in are the lengths of the sides of a triangle.
In option B,
![10+15=25>20](https://tex.z-dn.net/?f=10%2B15%3D25%3E20)
Sides 10 cm, 15 cm, 20 cm are the lengths of the sides of a triangle.
In option C,
![3+4=7>5](https://tex.z-dn.net/?f=3%2B4%3D7%3E5)
Sides 3 in, 4 in, 5 in are the lengths of the sides of a triangle.
In option D,
![8+5=13](https://tex.z-dn.net/?f=8%2B5%3D13%3C15)
Since, the sum of two smaller sides is less than the longest side, therefore the sides 8 ft, 15 ft, 5 ft are not the lengths of the sides of a triangle.
Therefore, the correct option is D.
Direct variation is of the form y=kx. We are given the point (8, -4) so we can solve for k, the constant of variation...
-4=8k, divide both sides by 8
-4/8=k
k=-0.5, so our equation is:
y=-0.5x,
Answer:
No, it is not.
Step-by-step explanation:
The decimal value of 12/4 is 3
The decimal value of 3/12 is 0.25