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NikAS [45]
4 years ago
9

Solve 0.9(x-20)=830

Mathematics
1 answer:
Dmitry [639]4 years ago
7 0

Answer:

942.22

Step-by-step explanation:

0.9(x-20)=830

Distribute .9

.9x -18 =830

Add 18 to each side

.9x -18+18=830+18

.9x = 848

Divide each side by .9

.9x/.9 = 848/.9

x =942.22222222

To the nearest hundredth

942.22

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In the diagram, the only figure that could be parallel to linec<br> IS
Alina [70]

Answer:

Could you post a picture of the diagram? One way to check is to graph them and see if the intersect, or see if they do any transversal behavior, or if the there is a line between the parallel lines that is perpendicular to both.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
John wants to measure the height of a tree. He walks exactly 100 feet from the base of the tree and looks up. The angle from the
kenny6666 [7]

Answer:

The height of the tree is 64.94\ ft

Step-by-step explanation:

Let

y ----> the height of the tree

we know that

tan(33\°)=y/100 ----> the function tangent is equal to divide the opposite side angle of 33 degrees by the adjacent side angle of 33 degrees

Solve for y

y=(100)tan(33\°)=64.94\ ft

5 0
3 years ago
Anybody know the answer?
marysya [2.9K]
I'd start by writing an equation for each of the right triangles. (Pythagorean theorem)

y² + 9² = z²
x² + z² = (4+9)²
4² + y² = x²

we want to find z so combine the equations by substituting the other variables x,y out.

substitute y² for (x² - 4²) in 1st equation.

(x² - 4²) + 9² = z²

now by rearranging the 2nd equation we can substitute x² for (13² - z²)

(13² - z²) - 4² + 9² = z²
169 - z² - 16 + 81 = z²
234 - z² = z²
234 = 2z²
234/2 = z²
117 = z²
√(117) = z
√(9*13) = z
3√(13) = z

13 goes in the box




































6 0
3 years ago
Use the formula d=rt. find t for r=39.5 m/h and d=402.9m
meriva
10.2. I hope this helps!
6 0
3 years ago
The Tower of Pisa is well known worldwide for how it leans,
ivann1987 [24]

Answer:

The tower is approximately 57.34 meters long

Step-by-step explanation:

The given parameters are;

The type of triangle formed by ΔABC = Non-right triangle

The measure of ∠ACB = 55°

The horizontal displacement of the tower, BX = 5 m

The length of BC = 45 m

Therefore, we have;

Triangle ΔABC type = Right triangle

By the tangent to an acute angle, θ, in a right triangle, we have;

Tan(\theta) = \dfrac{Opposite \, side \  length}{Adjacent\, side \ length}

Where θ is the 55°, we have angle, we have;

Tan(55^{\circ}) = \dfrac{XA}{XC}

BC = BX + XC

∴ XC = BC - BX

XC = 45 m - 5 m = 40 m

\therefore Tan(55^{\circ}) = \dfrac{XA}{40}

XA = 40 × tan(55°) ≈ 57.126

The type of triangle formed by ΔABX = Right triangle

According to Pythagoras theorem, AB² = XA² + BX²

∴ AB = √((40 × tan(55°))² + 5²) ≈ 57.34

The length of the tower, AB ≈ 57.34 m

6 0
3 years ago
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