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irina1246 [14]
3 years ago
8

Reduce 18/32 to lowest terms

Mathematics
2 answers:
erastova [34]3 years ago
6 0
Reducing to lowest terms simply means dividing both the numerator and the denominator by the same amount so as to get an equivalent fraction that has lower numbers so it looks nicer.

For example, we know that 1/4 = 2/8 = 4/16 = 10/40.

So for 18/32, let's start by diving both numbers by 2, to give 9/16. 9 and 16 can't be divided by the same number so 18/32 in it's lowest terms is 9/16.
devlian [24]3 years ago
4 0
By lowest terms, it simply means to it's simplest form. To do that, you have to find a number that can divide the two numbers involved. That number is 2. When 2 divides 18, you get 9. When 2 divides 32, you get 16. So you get;
9/16. And that is the final answer because nothing else can divide the two numbers. To make you understand better, i am using a different fraction. So;
16/8
  Once again, 2 can divide. But you can also use 8. If you use 2, it will be 8/4, 2 can still divide, so that will be 4/2. 2 divides again, making it 2/1, which is the same as 2.
   If you use 8, it will be 2/1. Which is still 2. So as you can see, no matter the number used, the answer remains the same. Hope i helped. Have a nice day.
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What is the value of x?<br> 6.75+ x = 131
yanalaym [24]

Answer:

x = 497/4 = 124.250

Step-by-step explanation:

Step  1  :

           27

Simplify   ——

           4

Equation at the end of step  1  :

  27          

 (—— +  x) -  131  = 0

  4          

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Adding a whole to a fraction

Rewrite the whole as a fraction using  4  as the denominator :

        x     x • 4

   x =  —  =  —————

        1       4  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

27 + x • 4     4x + 27

——————————  =  ———————

    4             4  

Equation at the end of step  2  :

 (4x + 27)    

 ————————— -  131  = 0

     4        

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  4  as the denominator :

          131     131 • 4

   131 =  ———  =  ———————

           1         4  

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

(4x+27) - (131 • 4)     4x - 497

———————————————————  =  ————————

         4                 4    

Equation at the end of step  3  :

 4x - 497

 ————————  = 0

    4    

Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, multiplys both sides of the equation by the denominator

Here's how:

 4x-497

 —————— • 4 = 0 • 4

   4  

Now, on the left hand side, the  4  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  4x-497  = 0

Solving a Single Variable Equation :

4.2      Solve  :    4x-497 = 0

Add  497  to both sides of the equation :

                     4x = 497

Divide both sides of the equation by 4:

                    x = 497/4 = 124.250

One solution was found :

                  x = 497/4 = 124.250

Processing ends successfully

plz mark me as brainliest :)

6 0
3 years ago
What is the value of 5(y+3)-3x2 when x=4 and y=2? <br> A. –23 <br> B. –10 <br> C. 10 <br> D. 23
pentagon [3]

Answer:

A !

Step-by-step explanation:

Substitute the value of the variable into the expression and simplify.

Hope this helps!

                                                   -Lei

3 0
2 years ago
Read 2 more answers
What side do DEC and EDB have in common?
pav-90 [236]

<u><em>Answer:</em></u>

DE is the common side in the two triangles


<u><em>Explanation:</em></u>

The side of the triangle is named based on its start and end points

A triangle is named based on its three vertices where each two vertices would join forming a side


<u>For ΔDEC, the sides are:</u>

DE, EC and DC


<u>For ΔEDB, the sides are:</u>

ED, DB and EB


By comparing the two triangles, we would find that DE is the common side in both triangles


Note: The visual illustration is in the attached image


Hope this helps :)

7 0
2 years ago
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At the zoo tje ratio of snakes to lizards is 3:2 A. If there were 10 lizards ,how many snakes would be there be? B.If there were
yawa3891 [41]

Answer:

Part A) 15\ snakes

Part B) 6\ lizards

Part C) The zoo would need to get four more lizards to maintain the same proportion

Part D) 12 snakes and 8 lizards

Step-by-step explanation:

Part A) If there were 10 lizards ,how many snakes would be there be?

Let

x ---> the number of snakes

y ---> the number of lizards

\frac{x}{y}=\frac{3}{2} ----> equation A

we have that

y=10\ lizards

substitute the value of y in the equation A

\frac{x}{10}=\frac{3}{2}

solve for x

x=10(3)/2\\x=15\ snakes

Part B) If there were 9 snakes ,how many lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

\frac{x}{y}=\frac{3}{2} ----> equation A

we have that

x=9\ snakes

substitute the value of x in the equation A

\frac{9}{y}=\frac{3}{2}

solve for y

y=9(2)/3\\y=6\ lizards

Part C) If the number of snakes in the zoo is increased by 6, how many more lizards would the zoo need to get to keep the same ratio?

Let

x ---> the number of snakes

y ---> the number of lizards

\frac{x}{y}=\frac{3}{2} ----> equation A

For x=6\ snakes

substitute the value of x in the equation A

\frac{6}{y}=\frac{3}{2}

solve for y

y=6(2)/3\\y=4\ lizards

therefore

The zoo would need to get four more lizards to maintain the same proportion

Part D) If the total number of snakes and lizards at the zoo was 20, how many snakes and lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

\frac{x}{y}=\frac{3}{2}

isolate the variable x

x=1.5y ----> equation A

x+y=20 ----> equation B

solve the system by substitution

substitute equation A in equation B

1.5y+y=20

solve for y

2.5y=20

y=8\ lizards

Find the value of x

x=1.5(8)=12\ snakes

therefore

12 snakes and 8 lizards

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Reduce the shapes using the scale factor 1/3
vlabodo [156]

Answer:

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