<span>There are 4 vans. So we have that probability that the first vehicle is a van p (e) = 4/10 = 0.4.
P(e|f) = P( f and e) / p (f)
p(e) = 0.4 and p(f) = 3/9
P (f and e) = 0.40 * 0.33 = 0.132
So p(e|f) = 0.4 * 0.33/ 0.33 = 0.4
P(f and e) p(f) * p(e) = 0.4 * 0.33 = 0.132</span>
Number of students on the bus = 54
Students who will go to lunch first are =
of 54
=
Hence, 36 students will go first for lunch.
Answer:
***
Answers may vary depending on the person reading the graph.
It is hard to tell what they think crosses nicely.
For example, I decided that the graph crossed nicely at the following points:



Step-by-step explanation:
I see that the graph crosses at
,
, and
.
The equation
tells us the
-intercept is
since when
we have
.
The
-intercept for our graph is
. Therefore,
.
So far we have the equation:
.
Let's enter the other points creating a system of linear equations to solve:


Let's simplify:


Let's subtract 3 on both sides:


I choose to solve the system by elimination.
Let's multiply the top equation by -3:


Now adding the equations results in:

Divide both sides by 24:

Now using one of the equations we can find
:
with 


Add 13/6 on both sides:



Divide both sides by 2:


So we have the equation:

Let's evaluate
now:




Formulas tab > in the Function Library group, click Lookup & Reference button, select VLOOKUP. Type A3 in the Lookup_value argument box. Type Abbreviation in the Table_array argument box. Type 2 in the Col_num argument box. Type False in the Rang_lookup box. Click OK, is this what you were looking for?
In a bag of snack mix:
n = nuts d = dried fruit
n = 744g d = ???g
Ratio Nuts/Dried fruit = 12/13
This basically means that if the mix was divided in 25 parts, 12 parts would be nuts and 13 would be dried fruits
If 744 is 12 parts then 744/12 is 1 part
744/12 = 62
1 part = 62g
there are 13 parts of dried fruit
13 x 62 = 806
744g of nuts + 806g of dreid fruit = 1550g
Answer: A batch of snack mix weigh 1550g, or 1.55kg
hope it helps :)