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marta [7]
2 years ago
5

Normal probability Density Function Use a graphing utility to graph the model probability density function with ð = 1 and µ = 2,

1, and 3
in the same viewing window.What effect does the mean µ have on the function?Explain your reasoning.

Mathematics
1 answer:
denpristay [2]2 years ago
7 0

Answer:

Step-by-step explanation:

Hello!

The population mean (μ) is a measure of central tendency, this means, it shows you the position of the distribution. Changing the value of the mean changes the position of the bell over the axis but there is no change in its shape. The three normal distribution have the same standard deviation (δ), so they will have the same shape and only their positions vary.

Graph attached.

I hope it helps!

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Isabel has 6.75 bags of coffee. A full bag weighs 5.2 pounds. How many pounds of coffee does Isabel have? *
lisabon 2012 [21]

Answer:

35.1

Step-by-step explanation:

6.75x5.2=35.1

3 0
2 years ago
1. In which quadrant or on which axis do each of the points (-2,4) , (3,-1) ,(-1,0), (1,2) and (-3,-5) lie? Verify your answer b
pashok25 [27]

Point (-2 , 4) lies in the 2nd quadrant

Point (3 , -1) lies in the 4th quadrant

Point (-1 , 0) lies on the negative part of the x-axis

Point (1 , 2) lies in the 1st quadrant

Point (-3 , -5) lies in the 3rd quadrant

Step-by-step explanation:

Let us revise the signs of the coordinates in each quadrant

  • x and y coordinates are positive in the 1st quadrant
  • x-coordinate is negative and y-coordinate is positive in the 2nd quadrant
  • x and y coordinates are negative in the 3rd quadrant
  • x-coordinate is positive and y-coordinate is negative in the 4th quadrant
  • The general point on the positive part of x-axis is (x , 0), and on the negative part of x-axis is (-x , 0)
  • The general point on the positive part of y-axis is (0 , y), and on the negative part of y-axis is (0 , -y)

Now let us check the points

Point (-2 , 4) ⇒ red point

∵ x = -2 and y = 4

∵ x-coordinate is negative and y-coordinate is positive

∴ Point (-2 , 4) lies in the 2nd quadrant

Point (3 , -1) ⇒ blue point

∵ x = 3 and y = -1

∵ x-coordinate is positive and y-coordinate is negative

∴ Point (3 , -1) lies in the 4th quadrant

Point (-1 , 0) ⇒ green point

∵ x = -1 and y = 0

∵ x-coordinate is negative and y-coordinate is zero

∴ Point (-1 , 0) lies on the negative part of the x-axis

Point (1 , 2) ⇒ purple point

∵ x = 1 and y =2

∵ x and y coordinates are positive

∴ Point (1 , 2) lies in the 1st quadrant

Point (-3 , -5) ⇒ black point

∵ x = -3 and y = -5

∵ x and y coordinates are negative

∴ Point (-3 , -5) lies in the 3rd quadrant

<em>Look to the attached graph for more understand</em>

Learn more:

You can learn more about the four quadrant in brainly.com/question/9381523

#LearnwithBrainly

5 0
2 years ago
What is the answer i need answers now
ad-work [718]
The answer is 10/3. Because you have 3 wholes and 1/3 so, 3x3 is 9 and you still have the extra 1 so 9+1=10 therefore your answer would be 10/3
5 0
1 year ago
Read 2 more answers
Write the equation of a circle in standard form with a diameter whose endpoints are
vova2212 [387]
X
x {}^{2}  + y {}^{2}  = r {}^{2}
4 0
3 years ago
Evaluate
sineoko [7]

We conclude that the equation evaluated in t = 6 and u = 14 is equal to 412.

<h3>How to evaluate an expression?</h3>

Here we have an expression with two variables, t and u.

6t - 32u

And we want to evaluate it in t = 6 and u = 14.

This means that we need to replace the two variables in the equation by the given numbers, so we replace the "t" with a 6, and the "u" with a 14, doing that we get:

6*6 - 32*14

Now we can solve that:

6*6 - 32*14

36 - 448 =  412

We conclude that the equation evaluated in t = 6 and u = 14 is equal to 412.

If you want to learn more about evaluating expressions:

brainly.com/question/4344214

#SPJ1

3 0
1 year ago
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