This is the concept of scale factor. The linear scale factor is given by:
(height of sculpture)/(height of clothespin)
=20/(5/12)
=48
Given that a woman is 5ft 7 in, the sculpture of this woman would be:
height of sculpture=(scale factor)*(height of the woman)
height of the woman=5 ft 7 inches=5 7/12 ft=67/12 ft
hence the height of the sculpture will be:
67/12×48
=268 ft
Answer: 268 ft
Abraham has 6 jawbreakers.
Isaac has 13 lollipops.
Jacob has 9 peanut butter cups.
If Ahmed ... one of Rebecca's camels that can't resist candy ...
makes the rounds in the middle of the night, breaks into each
of their tents, and eats all of the patriarchs' sweets, how many
pieces of candy will Ahmed the camel eat before sunrise ?
Answer: 25%
Step-by-step explanation:
Given: A rectangle has length 4 inches and width 2 inches.
Area = Length x width
= 4 inches x 2 inches
= 8 square inches
If length is reduced by 50% , then length 
If width is reduced by 50% , then length 
Reduced area = (reduced length) x (reduced width)
= 2 inches x 1 inch
= 2 square inches
The percentage of the area of the rectangle be reduced :-
Hence, the percent of the area of the rectangle be reduced = 25%
Step-by-step explanation:
as the velocity is not constant over time, we actually have to integrate v(t) over the interval 0<=t<=5 to get the distance.
v(t) = 60×ln(t + 1)
V(t) = 60 × integral(ln(t + 1)) between 0 and 5.
integral(ln(t + 1)) = (t + 1)ln(t + 1) - t + C
V(t) = 60 × ((t + 1)ln(t + 1) - t + C)
the distance traveled between t = 0 and t = 5 is then
60 × ((5 + 1)ln(5 + 1) - 5 + C) - 60 × ((0 + 1)ln(0 + 1) - 0 + C) =
= 60×(6ln(6) - 5 + C) - 60×(1ln(1) + C) =
= 60×(5.750556815... + C) - 60×C =
= 60×5.750556815... = 345.0334089... ≈ 345 km
Answer:
1. No, Student 1 did not make any errors. However, their use of a ruler, or lack of thereof, could result in a lack of accuracy.
2. The student manually found the points and connected them together, doing so for both A and B and thus finding the intersection.
3. Since there is no formula used, the result may not be accurate. The student can only guess the position of the intersection, not know exactly (i.e. when the points are positioned at decimal numbers.)
