D ( AC ) = 6 ( because A and C have the same y-coordinate )
d ( AB ) = √[(x2 - x1)² + (y2 - y1)²],
where A ( x1, y1 ) = ( -3, 1 ) and B ( x2, y2 ) = ( -1, 3 )
d ( AB ) = √[(-1 -(-3))² + (3 - 1 )²] = √[(-2)² + 2²] = √8 = 2√2
d ( BC ) = √[(3-(-1))² + (1-3)² =√[4² + (-2)²]= √20 = 2√5
The perimeter of ΔABC:
6 + 2√2 + 2√5 = 6 + 2 · 1.41 + 2 · 2.24 =
= 6 + 2.82 + 4.48 = 13.30
X^2 + x^2 =32
2x^2=32
x^2=16
x=4
M/IGJ will equal 52 degrees.
Since EGF is 90 degrees then and EGD equals 38 degrees you need to subtract 38 from 90 and you are left with 52 degrees for angle FGD. The alternate interior angle to FGD is IGJ which would make the angles congruent.
Answer: -x^3 - x^2 + 3x - 3
Glad I could help :D
Step-by-step explanation:
