Answer:
a2b+ca2+ab2-b2c+bc2-c2a-abc
Answer:
see explanation
Step-by-step explanation:
2 chords intersecting inside a circle , then the product of the parts of one chord is equal to the product of the parts of the other chord.
6
BE × ED = AE × CE , that is
10 × 3x = 12(2x + 1) ← distribute parenthesis by 12
30x = 24x + 12 ( subtract 24x from both sides )
6x = 12 ( divide both sides by 6 )
x = 2
then
ED = 3X = 3(2) = 6
7
RJ × JP = SJ × JQ , that is
6 × 3x = 4(4x + 1) ← distribute parenthesis by 4
18x = 16x + 4 ( subtract 16x from both sides )
2x = 4 ( divide both sides by 2 )
x = 2
then
RP = RJ + JP = 6 + 3x = 6 + 3(2) = 6 + 6 = 12
Let:
x = Desired Number
The information put into numbers would look like this:
x - 5 = 3
All we have to do is add 5 to both sides to get x on its own on the left and a single number on the right side, so:
x = 3 + 5
x = 8
Answer:
40 * 50 = 2,000
Step-by-step explanation:
Answer:
k=<u>7x^(2)-4x^(2)y^(2)-3xy+3</u>
x^(2)y^(2)-xy
pretend the underline is like the line for a fraction/ division
Step-by-step explanation:
