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Soloha48 [4]
3 years ago
15

Simplify (-5x^3)^-2 using only positive exponents

Mathematics
2 answers:
mihalych1998 [28]3 years ago
5 0
Hope you know that x^(-1) = 1/x  used this you get 

(-5x^3)^-2 = 1/(-5x^3)^2 = 1/{(-5^2)(x^6)} = 1/(25x^6)

hope helped 
Alona [7]3 years ago
4 0
a^{-n}=\dfrac{1}{a^n}\\\\(a^n)^m=a^{n\cdot m}\\\\(a\cdot b)^n=a^n\cdot b^n\\------------------\\\\\left(-5x^3\right)^{-2}=\dfrac{1}{\left(-5x^3\right)^2}=\dfrac{1}{(-5)^2(x^3)^2}=\dfrac{1}{25x^{3\cdot2}}=\boxed{\dfrac{1}{25x^6}}
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2x * \frac{8}{3}x=139 \ 968  \\ \\ \frac{16}{3}x^2= 139 \ 968 \\\\ x^2=139 \ 968: \frac{16}{3}=139 \ 968 * \frac{3}{16}=  8 \ 748*3 = 26 \ 244 \\  \\ x= \sqrt{26 \ 244} = 162 \ mm

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statuscvo [17]

Answer:

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Step-by-step explanation:

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and

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Consider the squares of the sum and product of roots:

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Then the equation with roots 1/p and 1/q is ...

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6 0
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