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lidiya [134]
3 years ago
12

10. how does the stranger show that he is more aggressive than henry when interacting with elisa at her garden? a. he refuses to

enter elisa's garden even when invited, while henry often enters without her permission. b. he barges right into elisa's garden without permission, while henry politely asks her several times if he may enter. c. he leans over the fence and eventually enters elisa's garden, while henry respects her space and remains outside. d. he makes fun of elisa's chrysanthemums, while henry often helps elisa when she's working on the garden.
Mathematics
2 answers:
Natalka [10]3 years ago
7 0
Based on the given question above, the option that shows how the stranger show that he is more aggressive than Henry when interacting with Elisa at her garden is that, he leans over the fence and eventually enters Elisa's garden, while Henry respects her space and remains outside. The correct answer would be option C. 
forsale [732]3 years ago
3 0

Answer:

he leans over the fence and eventually enters Elisa's garden while Henry respects her space and remains outside

Step-by-step explanation:

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For what value of k will k+9,2k-1 and 2k+7 are the consecutive terms of an A.P
Stolb23 [73]

k = 18

the common difference d of an arithmetic sequence is

d = a₂ - a₁ = a₃ - a₂ = ....

a₂ - a₁ = 2k - 1 - k - 9 = k - 10 and

a₃ - a₂ = 2k + 7 - (2k - 1) = 2k + 7 - 2k + 1 = 8, hence

k - 10 = 8 ⇒ k = 8 + 10 = 18

the 3 consecutive terms are

27, 35, 43


8 0
3 years ago
The length of a parking lot is 4 yards more than the width. If the area of the parking lot is 60 square yards, find the dimensio
zloy xaker [14]
Width = x
Length =x+4

X(x+4)=60

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(X+10)(x-4)

X=-10 and 4

Can’t use -10. So the answer is width =4. Length =8
7 0
3 years ago
The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in gr
raketka [301]

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass <em>M</em>₀, the mass after 12 hours is half that:

1/2 <em>M</em>₀ = <em>M</em>₀ exp(12<em>k</em>)

for some decay constant <em>k</em>. Solve for this <em>k</em> :

1/2 = exp(12<em>k</em>)

ln(1/2) = 12<em>k</em>

<em>k</em> = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass <em>M</em>₀, the mass <em>M</em> remaining after time <em>t</em> is given by

<em>M</em> = <em>M</em>₀ exp(<em>kt </em>)

So if <em>M</em>₀ = 590 g and <em>t</em> = 36 h, plugging these into the equation with the previously determined value of <em>k</em> gives

<em>M</em> = 590 exp(36<em>k</em>) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

6 0
3 years ago
Find the length of each side of a regular hexagon whose perimeter is 84 meters.
BaLLatris [955]

Answer:

84/6=14. Each side is 14 because there are 6 sides to a hexagon.

Step-by-step explanation:

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3 years ago
(fog) f(x) = 1/x g(x) square root x+3
NeX [460]

Answer:

see the step below, but I'm not sure if this you want

Step-by-step explanation:

(fog) =  \frac{1}{ \sqrt{x + 3} }

(fog) =  \frac{ \sqrt{ x  + 3} }{x + 3}

3 0
2 years ago
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