Answer:
Orange juice cups = 15
Mango juice cups = 6
Step-by-step explanation:
![\text{Fraction of orange cup used in one punch = }\frac{1}{2}\\\\\text{Fraction of mango cup used in one punch = }\frac{1}{5}\\\\\text{Now, to calculate the ratio : lcm of (2,5) = 10}\\\\So, Orange : Mango = \frac{1}{2}\times 10 :\frac{1}{5}\times 10=5:2\\\\\text{Now, required no. of orange juice cups = }\frac{\text{Orange cup ratio}}{\text{Sum of ratios}}\times 21\\\\=\frac{5}{7}\times 21=15\thinspace cups](https://tex.z-dn.net/?f=%5Ctext%7BFraction%20of%20orange%20cup%20used%20in%20one%20punch%20%3D%20%7D%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Ctext%7BFraction%20of%20mango%20cup%20used%20in%20one%20punch%20%3D%20%7D%5Cfrac%7B1%7D%7B5%7D%5C%5C%5C%5C%5Ctext%7BNow%2C%20to%20calculate%20the%20ratio%20%3A%20lcm%20of%20%282%2C5%29%20%3D%2010%7D%5C%5C%5C%5CSo%2C%20Orange%20%3A%20Mango%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%2010%20%3A%5Cfrac%7B1%7D%7B5%7D%5Ctimes%2010%3D5%3A2%5C%5C%5C%5C%5Ctext%7BNow%2C%20required%20no.%20of%20orange%20juice%20cups%20%3D%20%7D%5Cfrac%7B%5Ctext%7BOrange%20cup%20ratio%7D%7D%7B%5Ctext%7BSum%20of%20ratios%7D%7D%5Ctimes%2021%5C%5C%5C%5C%3D%5Cfrac%7B5%7D%7B7%7D%5Ctimes%2021%3D15%5Cthinspace%20cups)
![\text{Now, required no. of mango juice cups = }\frac{\text{Mango cup ratio}}{\text{Sum of ratios}}\times 21\\\\=\frac{2}{7}\times 21=6\thinspace cups](https://tex.z-dn.net/?f=%5Ctext%7BNow%2C%20required%20no.%20of%20mango%20juice%20cups%20%3D%20%7D%5Cfrac%7B%5Ctext%7BMango%20cup%20ratio%7D%7D%7B%5Ctext%7BSum%20of%20ratios%7D%7D%5Ctimes%2021%5C%5C%5C%5C%3D%5Cfrac%7B2%7D%7B7%7D%5Ctimes%2021%3D6%5Cthinspace%20cups)
Hence, No. of Orange juice cups needed to make 21 cups = 15 and no. of Mango juice cups needed to make 21 cups = 6
5:10:25. 1+2+5=8÷40=5×1=5. 5×2=10. 5×5=25 so 5:10:25
Categorical variables can assume values from a range of possible options, whereas quantitative variables can assume possibly infinitely many values from a certain number range.
So, the answer is "the colour of the bookshelf", because there can only be a limited number of possible colours for the bookshelf, whereas its width (no matter the unit measure) and height could be any number.
56.52 in^3
V(cylinder) = pi * r^2 * h
V = pi * 3^2 ^ 6
V = pi * 9 * 6
V = 54pi
V(sphere) = (4/3) * pi * r^3
V = (4/3) * pi * 3^3
V = (4/3) * pi * 27
V = 36pi
54pi - 36pi = 18 pi
18 * 3.14 = 56.52
Answer:
3
Step-by-step explanation:
s + 8 > 10
-8 -8
s > 2
(3) > 2
8+3=11
11 > 10