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larisa [96]
3 years ago
7

The price of a gallon of milk at a particular convenience store has been recorded over the course of 10 weeks. At the end of the

third week, the price $3.38 and at the end of the eighth week the price is $3.55. The price has been observed to increase exponentially.

Mathematics
1 answer:
katovenus [111]3 years ago
3 0

<u>Given:</u>

The price of milk at the end of the third week = $3.38.

The price of milk at the end of the eighth week = $3.55.

<u>To find:</u>

The approximate increase in price of milk per week and the cost of milk at the end of the tenth week.

<u>Solution:</u>

To determine the increase in the price per week, we divide the difference in price over n number of weeks by n.

Here we know the prices of milk at the end of the third and the eighth week. There are 5 weeks between these two.

The approximate increase in the price of milk = \frac{3.55-3.38}{5} = \frac{0.17}{5} = 0.034.

So there is an increase of $0.034 per week.

To determine the price at the end of the tenth week, we add the increase in price over two weeks to the price at the end of the eighth week.

The price of milk at the end of the eighth week = $3.55.

The increase in price over two weeks =2(0.034) = 0.068.

The price of the milk at the end of the tenth week = 3.55+0.068=3.618.

Rounding this off to the nearest cent, we get the price of milk at the end of the tenth week is $3.62.

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attashe74 [19]
Setup
45t = 40t + 60
5t = 60
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5 0
3 years ago
II'll mark brainliest who is the first to answer both questions correctly.
Strike441 [17]

Answer:

A) The probability that each player gets an ace, a 2 and a 3 with the order unimportant = (72/1925) = 0.0374

B) The probability of winning the jackpot = (1/1200) = 0.0008333

Step-by-step explanation:

A) There are four Aces, four 2's, and four 3's, forming a set of 12 cards

These cards are to be divided at random between 4 players.

What is the probability that each player gets an ace, a 2 and a 3.

We start with the first player, the probability of these cards for the first player, with order not important (because order isn't important, there are 6 different arrangement of the 3 cards)

6 × (4/12) × (4/11) × (4/10) = (16/55)

Then the second player getting that same order of cards

6 × (3/9) × (3/8) × (3/7) = (9/28)

Third player

6 × (2/6) × (2/5) × (2/4) = (2/5)

Fourth player

6 × (1/3) × (1/2) × (1/1) = 1

Probability that each of the players get different cards is then a multiple of the probabilities obtained above

= (16/55) × (9/28) × (2/5) × 1

= (288/7700) = (72/1925) = 0.0374

B) The concluding part of the B question.

To win the jackpot, the numbers on your ticket must match the three white balls and the SuperBall. (You don't need to match the white balls in order). If you buy a ticket, what is your probability of winning the jackpot?

Probability of wimning the jackpot is a product the probability of getting the 3 white balls correctly (order unimportant) and the probability of picking the right red superball

Probability of picking 3 white balls from 10

First slot, any of the 3 lucky numbers can fill this slot, (3/10)

Second slot, only 2 remaining lucky numbers can fill this slot, (2/9)

Third slot, only 1 remaining lucky number can fill this slot, (1/8)

(3/10) × (2/9) × (1/8) = (1/120)

Probability of picking the right red superball

(1/10)

Probability of winning the jackpot = (1/120) × (1/10) = (1/120) × (1/10) = (1/1200) = 0.0008333

Hope this Helps!!!

5 0
3 years ago
Need help with number 20
olga2289 [7]
4^4x = 8 
since 4 = 2^2  & 8= 2^3
so we can write the equation as 
(2^2)^4x = 2^3 
2^8x =2^3 
sp ,, 8x = 3 
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5 0
3 years ago
Suppose you are conducting a survey about the amount grocery store baggers are tipped for helping customers to their cars .for a
ELEN [110]

Using the Empirical Rule and the Central Limit Theorem, we have that:

  • About 68% of the sample mean fall with in the intervals $1.64 and $1.82.
  • About 99.7% of the sample mean fall with in the intervals $1.46 and $2.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

<h3>What does the Central Limit Theorem state?</h3>

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the standard deviation of the distribution of sample means is:

s = \frac{0.657}{\sqrt{50}} = 0.09

68% of the means are within 1 standard deviation of the mean, hence the bounds are:

  • 1.73 - 0.09 = $1.64.
  • 1.73 + 0.09 = $1.82.

99.7% of the means are within 3 standard deviations of the mean, hence the bounds are:

  • 1.73 - 3 x 0.09 = $1.46.
  • 1.73 + 3 x 0.09 = $2.

More can be learned about the Empirical Rule at brainly.com/question/24537145

#SPJ1

5 0
2 years ago
I need help for all of this problems!
Harlamova29_29 [7]
A) All triangles add up to 180° so when given two angles, add those up and subtract them from 180° . That will give you the missing angle.

3-5) When you do A above, and receive the measurement of angle 1, it will also equal 2 and you can repeat A for missing angle 3

6-8) Find the missing angle next to 1, and then subtract that from 180°. That number is the answer for 1. 2 is 55 as its a complimentary (i think thats the right term) angle. Which means it is on the opposite side of an angle. I don't remember how to find 3 however, its been a few years since I've done triangles.
4 0
4 years ago
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