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Airida [17]
3 years ago
12

Enter the explicit rule for the geometric sequence.

Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:  \frac{3}{2}(\frac{1}{2})^{n-1}

<u>Step-by-step explanation:</u>

\frac{3}{2}, \frac{3}{4}, \frac{3}{8}, \frac{3}{16}, \frac{3}{32}, ...

common ratio (r) = \frac{1}{2}

first term (a₁) = \frac{3}{2}

a_{n} = a₁ (r)ⁿ⁻¹

   = \frac{3}{2}(\frac{1}{2})^{n-1}

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Equation B is written in vertex form, which means you can read the vertex (extreme value) from the numbers in the equation.

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2 years ago
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3 years ago
What is the completely factored form of f(x) = 6x3 – 13x2 – 4x + 15?
masya89 [10]

We have to determine the complete factored form of the given polynomial

f(x)=6x^3-13x^2-4x+15.

Let x= -1 in the given polynomial.

So, f(-1)= 6(-1)^3-13(-1)^2-4(-1)+15 = -6-13+4+15 = 0

So, by factor theorem

(x+1) is a factor of the given polynomial.

So, dividing the given polynomial by (x+1), we get quotient as 6x^2-19x+15.

So, 6x^3-13x^2-4x+15 = (x+1)6x^2-19x+15.

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=(x+1)[ 2x(3x-5)-3(3x-5)]

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Option D is the correct answer.

5 0
2 years ago
Read 2 more answers
Given f(x)=4x+6 and g(x)=9x+9<br> then what is f(g(−6))?
irakobra [83]
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3 years ago
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