Simplify by factoring. What are the excluded values? Choose all that apply.

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

4 years ago

What are sets and Pls give examples

PilotLPTM [1.2K]

Is a collection of well defined and distinct objects.
Ex: ( A B C D E) all letters
Ex2: ( January, February, March, April) all months

6 0

3 years ago

Use the balanced scale to find the conversion factor that can be used to convert the number of blocks to the weight of the block

marusya05 [52]

Answer:

the answer is 24 lb

i think

Stepkby-step explanation:

it is 24 because it is 6 1lb blocks x 4 will give you 24

4 0

3 years ago

Read 2 more answers

The function, y(r)=2.76r , is used to convert Russian rubles in Japanese yen, and the function, P(y)=0.16y , is used to convert

timurjin [86]

They probably want 880 pesos, since they asked you do intermediate rounding

but a more accurate answer would be
883.20 pesos

To combine the functions, you'd substitute in 2.76r for y in 0.16y. This would give you 0.16(2.76r), which simplifies to 0.4416r, but they want you round this to the nearest hundredth, so its really 0.44r. Substitute in the 2000 for r and you get 0.44 * 2000 which is 880 pesos

5 0

3 years ago

Angel borrowed $141 to buy a stereo. He pays backs $14 each week. How much does he still owes after each week? Use a graph if yo

Harrizon [31]

Logically, he would owe 14 less each week

Let x = # of weeks passed

Algebraic Expression: 141 - 14x =

Week 1: 141 - 14 = 127

Week 2: 141 - 14(2) = 113

Week 3: 141 - 14(3) = 99

etc.....

Hope this helps

3 0

3 years ago