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2 years ago

Please help me at this wit steps how did you did it

Mathematics

1 answer:

balu736 [363]2 years ago

5 0

Answer:

5. LCM of 7 and 14: 14.

multiples of 7: 7, 14

multiples of 14: 14

LCM of 8 and 12: 24.

multiples of 8: 8, 16, 24

multiples of 12: 12, 24

Step-by-step explanation:

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Rina8888 [55]

83 hope it helps get a good grade

4 0

3 years ago

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Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am

zheka24 [161]

SOLUTION

We have been given the equation of the decay as

$\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}$

So we are looking for the time

Plugging the values into the equation, we have

$\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}$

Taking Ln of both sides, we have

$\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}$

Hence the answer is 4308 to the nearest year

8 0

6 months ago

Which statement is false?

Sidana [21]

Trigonometric functions which are related by having the same value at complementary angles are called cofunctions. Cofunctions of complementary angles are equal.

A. csc 20' = csc(90-70)=sec 70

B. cos 87' = cos (90-3)=sin 3'

C. csc 40' = csc(90-50) =sec50'

D. tan 15' = tan(90-75)= cot 75'

Among all the option c is not correct.

Option C is false.

8 0

3 years ago

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zloy xaker [14]

Answer:

The answer is 113.04

Step-by-step explanation:

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2 years ago

Need help on this please giving brainlest! :)

denis23 [38]

Answer:

a) (-4, 5)

b) (4, -5)

Step-by-step explanation:

Just reverse the signs or use desmos as a better example.

6 0

2 years ago

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