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4 years ago

Someone help me please thank you

Mathematics

2 answers:

UkoKoshka [18]4 years ago

6 0

It will take him 8 hours

Lerok [7]4 years ago

4 0

72/2 = 36 pages per hour

288/36=32/4=8

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jake can carry 6 1/4 pounds of wood in from the barn. His father can carry 1 5/7 times as much as Jake. How many pounds can Jake

Studentka2010 [4]

It would be: 6 1/4 * 1 5/7
= 25/4 * 12/7
= 300/28 = 150/14 = 75/7

In short, Your Answer would be 75/7 or 10 5/7 Pounds

Hope this helps!

4 0

3 years ago

Y decreased by 9is 8

olga55 [171]

Answer:

It's easy to figure it out. The equation we have is 8 = y - 9. We need to isolate y. Simply add 9 to each side of the equation to get this: 17 = y.

ANSWER: 17 = y

8 0

3 years ago

Members of the student concil are conducting a fundraiser by selling school calendars. After selling 80 calendars, they had a lo

Oksana_A [137]

Answer:

a) $y=8x-1000$

b) $profit=\$8$

c) They'd have lost $1000 if they had sold no calendars.

Step-by-step explanation:

a) The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

In this case we know that "y" represents the profit of loss and "x" the number of calendars sold.

Then, according to the exercise, the line passes through these two points:

$(80,-360)$ and $(200,600)$

Then, we can find the slope of the line with the formula $m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-360-600}{80-200}=8$

Now, we can substitute the slope and one of those points into $y=mx+b$ and solve for "b":

$600=8(200)+b\\\\b=-1000$

Then, subtituting values, we get that the equation that describes the relation between the profit of loss and the number of calendars sold, is:

$y=8x-1000$

b) The slope of the line is the profit they made from selling each calendar

$profit=8$

c) The y-intercept is the amount they would have lost if they had sold no calendars:

$b=-1000$

They'd have lost $1000 if they had sold no calendars.

6 0

3 years ago

Translations, rotations, and reflections are rigid transformations. What can you conclude about the measures of sides and angles

attashe74 [19]

Answer:

After a translation, the measures of the sides and angles on any triangle would be the same since translation only involves changing the coordinates of the vertices of the triangle.

After a rotation, the measures of the sides and angles of a triangle would also be the same. Similar to translation, the proportion of the triangle is unchanged after a rotation.

After a reflection, the triangle's sides and angles would still be the same since reflection is a rigid transformation and the proportion of the sides and angles are not changed.

Step-by-step explanation:

Rigid transformations, i.e. translations, rotations, and reflections, preserve the side lengths and angles of any figure. Therefore, after undergoing a series of rigid transformations, the side lengths and angle measures of any triangle will be the same as the original triangle, generally speaking, in another position.

4 0

3 years ago

4. MAIL It cost Ramon $3.73 to mail a package to his grandmother. The post

Alex Ar [27]

Answer:

4 pounds

Step-by-step explanation:

First, I subtracted the cost of the first pound from the final product (3.73 - 2.38) and I got 1.35. I then divided the 1.35 by .45 (the 45 cents) to figure out how many more pounds the package was from the initial 1 pounds. 1.35/.45 is 3, plus the 1 pound from the beginning makes 4 pounds in total.

6 0

3 years ago