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boyakko [2]
3 years ago
7

the volume of a rectangular prism with base dimensions of 3 cm and 8 cm and a prism height of 12 cm is?

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0
228 cm^3 is the answer. V=Bh
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What is<br> 3a+6b= 4 for b<br> Really need help
saw5 [17]

3a+6b=4

-3a both sides

6b=4-3a

÷6 both sides

b=2/3 -1/2 a

5 0
3 years ago
Calculate the side lengths a and b to two decimal places
Talja [164]

Answer:

The answer is (D) ⇒ a = 11.71 , b = 15.56

Step-by-step explanation:

* In ΔABC

∵ m∠A = 45°

∵ m∠B = 110°

∴ m∠C = 180 - 45 - 110 = 25°

By using the sin Rule

∵ a/sin(A) = b/sin(B) = c/sin(C)

∵ c = 7

∴ a/sin(45) = b/sin(110) = 7/sin(25)

∴ a = (7 × sin(45)) ÷ sin(25) = 11.71

∴ b = (7 × sin(110)) ÷ sin(25) = 15.56

∴ The answer is (D)

5 0
3 years ago
A regular pentagon with side length s has perimeter 5s. Dakota built a dog pen in her backyard for her dog's new puppies. The pe
sashaice [31]
The answer is 243 hope this helps
4 0
3 years ago
Need help solving it. Quantitative Literacy.
ioda

1 lb ≈ 0.454 kg

1 in ≈ 2.54 cm

I'm not sure I understand the "do not" part of this question. What does it mean to convert from cubic inches (volume) to inches (length), and from centimeter to cubic centimeters?

In any case, you have

(1 lb)/(32.375 in³) ≈ (1 lb)/(3.19 in)³

… ≈ (1 lb)/(3.19 in)³ × (0.454 kg)/(1 lb) × ((1 in)/(2.54 cm))³

… ≈ (0.454 kg)/(3.19 in)³ × ((1 in)/(2.54 cm))³

… ≈ (0.454 kg) × ((1 in)/((3.19 in) × (2.54 cm))³

… ≈ (0.454 kg) × (1/(8.10 cm))³

… ≈ (0.454 kg) × 1/(530.531 cm³)

… ≈ (0.454 kg)/(530.531 cm³)

… ≈ 0.000856 kg/cm³

5 0
3 years ago
The graphed line shown below is y = 5 x minus 10. On a coordinate plane, a line goes through (2, 0) and (3, 5). Which equation,
anygoal [31]

Answer:

The correct option is:

y = 5(x-2)

Step-by-step explanation:

The graphed line is;

y = 5x - 10

y = mx + c

Thus, slope of graphed line is equal to m=5.

Those line will have no solution which have are parallel to the graphed line (have a slope of 5) and passes through the given points.

Following lines have the slopes 5:

y= 5(x+2)

y= 5(x-2)

Check which equation satisfied points (2,0) and (3,5)

For (2,0)

y=5(x-2)

y=5(2-2)

y=0

For (3,5)

y=5(x-2)

y=5(3-2)

y=5

Thus, correct option is y = 5(x-2)

5 0
3 years ago
Read 2 more answers
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