Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
Answer:
9x is the answer
Step-by-step explanation:
-x-(-10x)
-x+10x
9x
For this case we have a quadratic equation, 
, of the form 
Where:
We can solve the equation by factoring, that is, we bias two numbers that multiplied give as a result -60 and added as a result 28.
These numbers are:
Then, the factorization is given by:
The roots are:
Answer:
Answer:
3x + 1/2x
Step-by-step explanation:
Just replace "a number" with x
"Three times x added to half x"
Answer: c. (1/2) bc sin A
<u>Step-by-step explanation:</u>
You can find the area of a triangle using trigonometry if you know the lengths of two sides and the measure of the included angle using the following formula:
