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3 years ago

I need help what is 7- 5 6/7?

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

4 0

1/7 I don't know if this is subtract or not but I subtracted

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Identify the slope and y-intercept: y = -1/5x+12 Slope: y-intercept:

ipn [44]

Answer:

Slope: -1/5 y-intercept: 12

Step-by-step explanation:

y = -1/5x + 12

The equation given is the slope-intercept form, y= mx + b

In this equation, the m, or number in front of the x, is the slope of the line.

The b in the equation represents the y-intercept.

Therefore, according to the given equation, the slope is -1/5 and the y-intercept is 12.

8 0

3 years ago

Any face that is not a base

Ann [662]

Answer:

In Mathematics Geometry, lateral face is said be the side of a 3D-figure in that is not a base.

Please check the attached figure to visual the concept.

Step-by-step explanation:

In Mathematics Geometry, lateral face is said be the side of a 3D-figure in that is not a base.

The faces in in a prism or pyramid which are not bases are basically the lateral faces.

For example, the lateral faces are basically parallelograms in Triangular prism which are not the bases.

Please check the attached figure to visual the concept.

7 0

3 years ago

(2,4) (0,y) slope is -2

solong [7]

-2= y-4
——
0-2
-2= y-4
——
-2
(y-4)•-2 = -2
-2y+8=-2
-2y=-10
————
-2
y=5
hope this helps

8 0

4 years ago

In circle F with the measure of minor arc EG = 122, finh m

pickupchik [31]

Answer:

MEASURE OF F WILL BE 58°

Step-by-step explanation:

HOPE IT HELPS YOU

5 0

3 years ago

Read 2 more answers

Find an equation of the plane with x-intercept a, y-intercept b, and z-intercept c. What is the distance between the origin and

Elenna [48]

Answer:

The equation is:

(1/a)x + (1/b)y + (1/c)z = 1

Step-by-step explanation:

The direction vector between the points (a, 0, 0) and (0, b, 0) is given as:

<0 - a, b - 0, 0 - 0>

<-a, b, 0> .....................(1)

The direction vector between (0, 0, c) and (0, b, 0) is given as:

<0 - 0, b - 0, 0 - c>

= <0, b, -c> .....................(2)

To obtain the direction vector that is normal to the surface of the plane, we take the cross product of (1) and (2).

Doing this, we have:

<-a, b, 0> × <0, b, -c> = <-bc, -ac, -ab>

To find the scalar equation of the plane we can use any of the points that we know. Using (0, b, 0), we have:

(-bc)x + (-ac)y + (-ab)z = (-bc)0 + (-ac)b + (-ab)0

(bc)x + (ac)y + (ab)z = (ac)b

Dividing both sides by abc, we have:

(1/a)x + (1/b)y + (1/c)z = 1

3 0

3 years ago