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3 years ago

How much popcorn can you buy per dollar? Do not include units (oz) in your answer.

Mathematics

1 answer:

mezya [45]3 years ago

7 0

Answer:

there should be more ;-;

you can buy a basically any popcorn in the dollar store ;-;

Step-by-step explanation:

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Solve for x: |2x + 12| = 18

Mashcka [7]

2x + 12 = 18
18 - 12 = 6
2x = 6
x = 3

7 0

3 years ago

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Which of the following represents the graph of f(x) = 2x + 2?

Wittaler [7]

Did u type the equation wrong none of these graphs match I believe the intercept would be 2

3 0

3 years ago

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Shortern this expression pls

pogonyaev

Answer:

$c =\frac{8}{3}$

Step-by-step explanation:

Given

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Required

Shorten

We have:

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Rationalize

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}$

Expand

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} + \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} + \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} + \sqrt{\frac{(4 - \sqrt 7)^2}{9}$

Take positive square roots

$c =\frac{4 + \sqrt 7}{3} + \frac{4 - \sqrt 7}{3}$

Take LCM

$c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}$

Collect like terms

$c =\frac{4 + 4+ \sqrt 7 - \sqrt 7}{3}$

$c =\frac{8}{3}$

4 0

3 years ago

Simplify ( -12) x ( 13) x (-15) Please give explanation fast please

kherson [118]

Answer:

2340

Step-by-step explanation:

(-12)×(13)×(-15)

=(-156)×(-15)[ (+) × (-) = (-)]

=2340[(-) × (-) = (+)]

5 0

3 years ago

PQ is rotated 180 degrees clockwise about P. What are the coordinates of P' and Q'?

Salsk061 [2.6K]

The co ordinates of P' is (-7,-2) and Q' is (-16, -8)

Explanation

PQ is rotated 180 degrees clockwise about P. It means P and P' are the same points.

According to the graph, the coordinates of P is (-7, -2) and Q is (2, 4)

When PQ is rotated 180 degrees clockwise about P, then P or P' will be the mid-point of Q and Q'

Suppose, the co ordinate of Q' is (x, y)

Now according to the mid-point formula, the coordinate of P or P' will be: $(\frac{x+2}{2},\frac{y+4}{2})$ , which is actually at (-7, -2)

Thus.....

$\frac{x+2}{2}=-7\\ \\ x+2=-14\\ \\ x= -16\\ \\ and\\ \\ \frac{y+4}{2}= -2\\ \\ y+4= -4\\ \\ y= -8$

So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)

6 0

3 years ago