To isolate c means to separate it completely on one side of the equals sign.
To isolate variables, you apply opposite operations.
In E = mc², m and c are being multiplied together. To separate them, you divide by the variable you want to get rid of. However, you must do this to both sides of the equation always. Whatever you do to one side of the equation you must do to the other side as well. This is so the equation remains true.
Since we want to isolate c, we'll start by dividing both sides by m.
E = mc²
E/m = mc²/m
E/m = c² -- The m's cancel as 1
Now we have c squared. The opposite of squaring something is taking its square root. Take the square root of each side.
E/m = c²
√(E/m) = √(c²)
√(E/m) = c -- Opposite operations cancel each other out
And you've isolated c!
Answer:
c = √(E/m)
One line passes through the points (-2,3) and (0,-3) , it means the y intercept is b=-3
and slope m = 

So the equation of line will be 
And the inequality should be 
Or 
And the other line passes through (-2,3) and (0,2)
So the y intercept is b=2
and the slope is 
So the equation of line will be 
Or

So answer is 
Answer:
6
Step-by-step explanation:
3+x+x=15
3+2x=15
2x=15-3
2x=12
x=12/2
x=6
Hey
Question 1: For this one, we simply need to look at the "fat grams over 25" and the "Total" sections. We can see that 27 out of 50 have fat grams over 25. This written as a percentage is: 54%
Question 2: Using the same logic above we conclude the answer is 45.45%
Question 3: For this we need to look at the "total" section and the answer is 50
Question 4: We add all the "over 300" and write it as a percentage out of 50 which is 14%
Question 5: Same as #1 answer is 21%
Hope this helps
(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))
Recall that
tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)
so cos²(<em>θ</em>) cancels with the cos²(<em>θ</em>) in the tan²(<em>θ</em>) term:
(sin²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))
Recall the double angle identity for cosine,
cos(2<em>θ</em>) = 2 cos²(<em>θ</em>) - 1
so the 1 in the denominator also vanishes:
(sin²(<em>θ</em>) - 1) / (2 cos²(<em>θ</em>))
Recall the Pythagorean identity,
cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1
which means
sin²(<em>θ</em>) - 1 = -cos²(<em>θ</em>):
-cos²(<em>θ</em>) / (2 cos²(<em>θ</em>))
Cancel the cos²(<em>θ</em>) terms to end up with
(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>)) = -1/2