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VLD [36.1K]
4 years ago
12

different sizes of regular pentagons are used in a stained glass window.each small pentagon has side lengths of 4 inches and an

area of 27.5 square inches.each large pentagon has a side lengths of 8 inches.what is the area of each large pentagon?
Mathematics
1 answer:
Liula [17]4 years ago
7 0
The goal is to find the area of a pentagon with side length 8.

We can find the area of a pentagon very easily by splitting it up into 10 congruent right triangles with the apothem as the height. The base of one of these triangles would be 4. The base angle would be 54 degrees, because it's half of the angle of a regular pentagon.

Using trig we find that the height of this triangle/apothem of the pentagon is equal to 4tan(54 degrees), which is about 5.506.

The area of a triangle is bh/2, so...4*5.506/2 = 11.011 in².
Times 10 triangles is 110.11 in².

You might be interested in
Do modern scientists believe that protons and nuetrons are not made of smaller particles
anyanavicka [17]

Answer: Thus, protons and neutrons are no more indivisible than atoms are; indeed, they contain still smaller particles, which are called quarks. Quarks are as small as or smaller than physicists can measure.

Step-by-step explanation:

4 0
3 years ago
I need this pls helpp
alexandr1967 [171]

Answer:

m∠7 = 63 degrees

m∠8 = 117 degrees

m∠9 = 63 degrees

Step-by-step explanation:

When two lines intersect at a point, then they formed 2 pairs of vertically opposite angles and 4 pairs of linear angles

  • The vertically opposite angles are equal in measures
  • The linear angles have a sum of 180°

In the given figure

∵ There are two lines intersected at a point

∴ The angle of measure 117° and ∠8 are vertically opposite angles

∴ ∠7 and ∠9 are vertically opposite angles

∴ The angle of measure 117° and ∠7 are linear angles

∵ The vertically opposite angles are equal in measures

∴ The angle of measure 117° and ∠8 are equal in measures

∴ m∠8 = 117°

∵ The sum of the measures of the linear angles is 180°

∴ m∠7 + 117° = 180°

→ Subtract 118 from both sides

∵ m∠7 + 117 - 117 = 180 - 117

∴ m∠7 = 63°

∵ m∠7 = m∠9 ⇒ proved up

∴ m∠9 = 63°

3 0
3 years ago
Answer the question<br> 10 points
lubasha [3.4K]
The slope is 9 and the y intercept is 4.
7 0
3 years ago
Find the volume of the pyramid. Write your answer as a fraction or mixed number.
Dahasolnce [82]

Check the picture below.

let's notice that the base of the pyramid is triangle with a base of 5 and an altitude of 4, so it has an area of (1/2)(5)(4).

\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=\stackrel{\textit{area of its}}{base}\\ h=height\\[-0.5em] \hrulefill\\ B=\frac{1}{2}(5)(4)\\ h=8 \end{cases}\implies V=\cfrac{1}{3}\left( \cfrac{1}{2}(5)(4) \right)(8)\implies V=\cfrac{1}{3}(10)(8) \\\\\\ V=\cfrac{80}{3}\implies V=26\frac{2}{3}

4 0
4 years ago
One grocery clerk can stock a shelf in 20 min. A second clerk requires 45 min to stock the same shelf. How long would it take to
Lorico [155]

<u>Answer: </u>

clerk A and clerk B can simultaneously stock a shelf in \frac{180}{13} minutes

<u>Explanation:</u>

Let the first clerk be A and the second clerk be B

A can stock a shelf in 20 min

B can stock a shelf in 45 min

Consider the complete work to be W

A’s rate of stocking = \frac{W}{20} per minute

B’s rate of stocking = \frac{W}{45} per minute

When, A and B work simultaneously, rate of work done = \frac{W}{20}+\frac{W}{45}

Total work done simulatenously = \frac{W}{\frac{W}{20}+\frac{w}{45}}

=\frac{20 * 45}{20+45}

Therefore, clerk A and clerk B can simultaneously stock a shelf in \frac{180}{13} minutes

8 0
3 years ago
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