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3 years ago

Find the variable h+ 1/2 = 3 1/4

Mathematics

1 answer:

Elena L [17]3 years ago

7 0

Answer:

h=2 3/4

Step-by-step explanation:

2 3/4+1/2=

you can convert 1/2 into 2/4 so they have like denominators

2 3/4+2/4= 2 5/4 which is also equal to 3 1/4

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The volume of a box 4in wide 2in high and 5in long is

Free_Kalibri [48]

Answer:

40 cubic inches

Step-by-step explanation:

The Formula for Volume: Length x Width x Height (L x W x H)

4 times 2 times 5 = 40

6 0

3 years ago

What is the circumference of a circle if the radius is 50 ?

Zina [86]

The appropriate formula is C = 2*pi*r.

Here, C = 2*pi*(50 units) = 100*pi units (answer)

5 0

3 years ago

What trigonometric ratio is defined as the length of the opposite leg divided by the length of the hypotenuse?

aleksley [76]

SOH CAH TOA

Sine is opposite over hypotenuse so you're answer is C.

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8 0

3 years ago

Write a situation in which positive and negative numbers are used to describe values that have opposite meaning. What does a 0 r

MrRa [10]

This could be a situation in which items are both bought and sold. In calculating the inventory, positive numbers represent items bought, negative numbers represent items sold and 0 would be no items in the inventory.

Another type of situation would be the displacement of an object from the original position. Where 0 would represent the original/starting position, positive values would represent distance moved forward, negative values represent distance moved backwards.

4 0

3 years ago

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$

3 0

2 years ago