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d1i1m1o1n [39]
3 years ago
12

5xsquared plus 3x plus 4

Mathematics
1 answer:
GalinKa [24]3 years ago
6 0
5(x- (-3+√71i)/10) (x- (-3 - √71i)/10)
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Carly's age is more than twice his sisters age, s. Which of the following expressions represents Carly's age? (A) 2s + 3 (B) 3s
Ilya [14]
I would say A.

B would be Carly's age is two years more than three times his sister's age.

C would be Carly's age is two times his sister's age plus three

D would be Carly's age is his sister's age squared plus three.
5 0
3 years ago
Read 2 more answers
Perform the indicated operation.<br> 1 1/6 + 7 3/6 =<br><br> I HAVE 5 MINUTES!!!
gizmo_the_mogwai [7]

Answer:

1 1/6 - 7 3/6 = -19/

3

= -6 1/

3

≅ -6.3333333

Step-by-step explanation:

Conversion a mixed number 1 1/

6

to a improper fraction: 1 1/6 = 1 1/

6

= 1 · 6 + 1/

6

= 6 + 1/

6

= 7/

6

To find new numerator:

a) Multiply the whole number 1 by the denominator 6. Whole number 1 equally 1 * 6/

6

= 6/

6

b) Add the answer from previous step 6 to the numerator 1. New numerator is 6 + 1 = 7

c) Write a previous answer (new numerator 7) over the denominator 6.

One and one sixth is seven sixths

Conversion a mixed number 7 3/

6

to a improper fraction: 7 3/6 = 7 3/

6

= 7 · 6 + 3/

6

= 42 + 3/

6

= 45/

6

To find new numerator:

a) Multiply the whole number 7 by the denominator 6. Whole number 7 equally 7 * 6/

6

= 42/

6

b) Add the answer from previous step 42 to the numerator 3. New numerator is 42 + 3 = 45

c) Write a previous answer (new numerator 45) over the denominator 6.

Seven and three sixths is forty-five sixths

Subtract: 7/

6

- 45/

6

= 7 - 45/

6

= -38/

6

= 2 · -19/

2 · 3

= -19/

3

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(6, 6) = 6. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 6 × 6 = 36. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - seven sixths minus forty-five sixths = minus nineteen thirds.

4 0
3 years ago
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
F(x) = -6x-1<br> f(-1/2) = ?
UNO [17]

Answer:

Intersection point of this is (0,-0.5)

Step-by-step explanation:

Hope this helps :)

7 0
3 years ago
PLEASE HELP ME ASAP???!!!!!!!!
Ivenika [448]

Answer:

I'm very very sorry I cannot help you I wish I could help sorry bud.

8 0
3 years ago
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