2 years ago

Below are the graphs of the functions y=2x and y3x What is the same about both lines?

Mathematics

1 answer:

Yanka [14]2 years ago

5 0

C they rise upward toward the right

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The approximate distance between J and K is units. The approximate distance between K and L is units. The approximate distance b

Dima020 [189]

Count the distance d, which gives you 7.

Use Pythogarean theorem to find c:
${a}^{2} + {b}^{2} = {c}^{2}$
Plug in the numbers:
${4}^{2} + {3}^{2} = {c}^{2} \\ \\ = 16 + 9 \\ \\ = 25 \\ \\ c = \sqrt{25} = 5$
c is 5.

Same thing with g:
${e}^{2} + {f}^{2} = {g}^{2} \\ \\ {g}^{2} = {4}^{2} + {4}^{2} \\ \\ = 16 + 16 \\ \\ = 32 \\ \\ g = \sqrt{32} = 4 \sqrt{2} = 5.66$
g equals 5.66.

7 0

3 years ago

Can someone plssss helpp me with this!!! and show the work!

hichkok12 [17]

Answer:

1/2

Step-by-step explanation:

8(1/2)^4

= 8 * 1 / 2^4

= 8/(2*2*2*2)

= 8/16

= (8*1) / (8*2)

= 1/2

5 0

3 years ago

Simplify the expression.

spayn [35]

Answer:

C. $\huge\frac{1}{3x {y}^{2} {z}^{4}}$

Step-by-step explanation:

$(9 {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } \\ \\ = ( {3}^{2} {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } \\ \\ = \frac{1}{( {3}^{2} {x}^{2} {y}^{4} {z}^{8} )^{ \frac{1}{2} }} \\ \\ = \frac{1}{(3x {y}^{2} {z}^{4})^{2 \times \frac{1}{2} } } \\ \\ = \frac{1}{3x {y}^{2} {z}^{4}} \\ \\ \red{ \bold{ \therefore \: (9 {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } = \frac{1}{3x {y}^{2} {z}^{4}} }}\\$