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3 years ago

1×9=9 is a true statement which multiplication property is this example of? identity distributive associative communative

Mathematics

2 answers:

natta225 [31]3 years ago

7 0

I would say that this is associative property please let me know if its right, but i'm really positive i'm right.

olga2289 [7]3 years ago

5 0

Identity, which basically is any number times 1 will equal that number :)

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HELP ASAP WILL GIVE BRAINILIST ANSWER 8/3___19/7 A) > B) < C) =

Troyanec [42]

3*2=6
2 2/3

7*2=14
2 5/7

the answer is B)
good luck

6 0

3 years ago

Read 2 more answers

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

Put $(x,y)=(1,1)$

$\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9$

This is true.

So, the point $(1,1)$ satisfies the equation $\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

So, point H is $(1,1)$ .

7 0

3 years ago

Create a model showing 80% of 300

Vinil7 [7]

I made this graph for you- the red is the 80%, and the green is the leftover 20%.

8 0

3 years ago

Find the area of this figure. use 3.14 for pi.

Ganezh [65]

The square would be 100.
The semicircle you will use the formula πr^2/2.
That would mean you would take the 3.14x5^2/2.
(3.14x5x5)/2
(3.14x25)/2
78.5/2
=39.25
So the total area would be 139.25

7 0

3 years ago

Multiply y^2-16/2y . 5y/y-4

alisha [4.7K]

So, first we multiply the fraction by using the formula a/b times c/d= a times c/b times d
=(y^2-16) times 5y/2y(y-4)
Now, we cancel the common factor y
=(y^2-16) times 5/2(y-4)
Now, we factor 5(y^2-16)
We factor (y^2-16) first
y^2-16
Rewrite 16 as 4^2
y^2-4^2
Now, apply the formula x^2-y^2=(x+y)(x-y)
=y^2-4^2=(y+4)(y-4)
=5(y+4)(y-4)
=5(y+4)(y-4)/2(y-4)
Cancel the common factor y-4
=5(y+4)/2
Answer: 5(y+4)/2

5 0

3 years ago