Answer:
u line ub the decimals and s=do regular subtraction
Step-by-step explanation:
I think the answer would be -14
K = Kate's age nowJ = Joey's age nowK+5 = Kate's age in 5 yearsJ+5 = Joey's age in 5 years From the first sentenceK+5 = 2(J+5) From the second sentenceK=J+11 So our system of equations isK+5 = 2(J+5)K=J+11 The first equation is equivalent toK+5 = 2J+10or by rearranging termsK-2J=5 The second equation is equivalent toK-J=11 This gives us K-2J=5K-J=11 Using the elimination method, we need to multiply one of the equations by a factor such that we can eliminate one of the variables. This means we want one of the variables to have coefficients which are the same magnitude but opposite signs. We can do this by multiplying the 1st equation by -1. This give us -K+2J=-5 K - J = 11 Now add these two equations together, term by term. This gives usJ=6 So Joey is 6 years old now.
Answer:
23 and 24
Step-by-step explanation:
Answer:
There are many examples for the first request, but none for the second.
Step-by-step explanation:
a) There is a theorem which states that the sum of two convergent sequences is convergent, so any pair of convergent sequences (xn), (yn) will work (xn=1/n, yn=2/n, xn+yn=3/n. All of these converge to zero)
If you meant (xn) and (yn) to be both divergent, we can still find an example. Take (xn)=(n²) and (yn)=(1/n - n²). Then (xn) diverges to +∞ (n² is not bounded above and it is increasing), (yn) diverges to -∞ (1/n -n² is not bounded below, and this sequence is decreasing), but (xn+yn)=(1/n) converges to zero.
b) This is impossible. Suppose that (xn) converges and (xn+ýn) converges. Then (-xn) converges (scalar multiples of a convvergent sequence are convergent). Now, since sums of convergent sequences are convergent, (xn+yn+(-xn))=(yn) is a convergent sequence. Therefore, (yn) is not divergent and the example does not exist.
