The slope of line q is that of line p scaled by a factor of 3 (not -3). The y-intercept of line q is 6 less than the y-intercept of line p. The appropriate choice is
D. y = 3ax +b -6
Y= -1x + -1 is the answer
W=-5 because you distribute at the beginning with the 2 variables and you solve that's equation and you will end up with 6w divided by 30 and that's will give u W=-5
Answer:
The probability of selecting two Democrats and two Republicans is 0.4242.
Step-by-step explanation:
The information provided is as follows:
- A city council consists of seven Democrats and five Republicans.
- A committee of four people is selected.
In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.
The formula to compute the combinations of k items from n is given by the formula:

Compute the number of ways to select four people as follows:

Compute the number of ways to selected two Democrats as follows:

Compute the number of ways to selected two Republicans as follows:

Then the probability of selecting two Democrats and two Republicans as follows:

Thus, the probability of selecting two Democrats and two Republicans is 0.4242.
Answer: See explanation
Step-by-step explanation:
We are informed that Stephen rewrites 3r - 18 = 27 as 3(r - 6) = 3(9). This is quite thoughtful of Stephen and it's an easier way to solve the question.
In this case, 3 is a common factor to 3r, 18 and 27. Therefore, we will then have: 3(r - 6) = 3(9).
Since 3 is a common base to both, we are more concerned with the values inside the brackets. This will be:
r-6 = 9
r = 9 + 6
r = 15
Check: 3r - 18
3(15) - 18 = 45 - 18 = 27