Make the bottom numbers the same, do whatever you do to the bottom to the top, and add the top numbers.
Question
Marcus asked 10 people at a juggling festival what age they were when they started to juggle. Which interval contains the median age?
Answer:
See Explanation
Step-by-step explanation:
Given

Required
The median interval
The question is incomplete, as the required data is not given.
To solve this question, I will use the following assumed dataset.

First, calculate the median position.



This implies that the median is the mean of the 5th and 6th data
So, we have the interval to be.
![Median = [5th, 6th]](https://tex.z-dn.net/?f=Median%20%3D%20%5B5th%2C%206th%5D)
![Median=[21,22]](https://tex.z-dn.net/?f=Median%3D%5B21%2C22%5D)
<em>Generally, the median of 10 data set is located at interval 5 to 6</em>
Answer:
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jjjjStep-by-step explanation:
hjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
Answer: 
Step-by-step explanation:
Let be "y" the monthly demand for the company’s sports caps, "x" the amount in dollar spent on advertising and "z"the price ind dollars per cap.
The model for this situation is:

Where "k" is the constant of proportionality.
Since
when
and
, we can substitute values into
and solve for "k" to finds its value:

Then, in order to calculate what price yields a demand of 300 caps when advertising is increased to $3,000, we must substitute the following values into
:

Then:

Solving for "z" we get:

Answer:
No. of yellow balloons = r - b - 
Step-by-step explanation:
Total number of balloons = r
No of blue balloons = b
Blue balloons are twice the no of green balloons. so
No. of green balloons = 
No of yellow balloons = ( Total number of balloons ) - ( No of blue balloons ) - ( No. of green balloons )
⇒ No. of yellow balloons = r - b - 