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ratelena [41]
3 years ago
8

7. Our solutions are the

Mathematics
1 answer:
Alex777 [14]3 years ago
5 0
Please explain what yo
You might be interested in
What is he value of F(-3)
PolarNik [594]

The correct answer is: " 10 " .

___________________________________________

→ " f(-3) = 10 " .

___________________________________________

Explanation:

___________________________________________


Given:

___________________________________________


f(x) = 7 − x ; if: x ≤ -3 ;


f(x) = x + 4 ; if: x > -3 ;

_________________________________________


Find: " f(-3) " :

_________________________________________


Note:  " f(x) = f(-3) " ;  → " x = - 3 " ;


Since  " x  = -  =3 " ;   →  x is NOT greater than "-3" ;


→ So; " f(x) does NOT equal " x + 4" ;

_________________________________________

Consider our other option given:


We have "x = -3 " .


We our given: If " x ≤ -3 " ; {that is; if "x" is less than or equal to "-3" };


→  then: " f(x) =  7 −  x " .

______________________________________________


Since: " x = - 3 " ;


→ then " x ≤ -3 " ;  and:


→ f(x) = 7 − x  ;


THEN:


→ f(-3) = 7 − (-3) ;  →  Note:  Plug in "-3" for the value(s) of "x" in the equation;

and solve:

→         =  7  +  3 ;    

             =  10 .

___________________________________________________

→  f(-3)  =  10  .


_____________________________________

The answer is:  " 10 " .

_____________________________________

Hope this answer — and explanation — is helpful to you.

Best wishes in your academic pursuits!

_____________________________________

5 0
4 years ago
Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x
Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

y=a(x-h)^2+k  

(where (h, k) is the vertex)

Given:

  • vertex = (1, -108)

\implies y=a(x-1)^2-108

Given:

  • y-intercept = (0, -105)

\implies a(0-1)^2-108=-105

\implies a(-1)^2=-105+108

\implies a=3

Therefore:

\implies y=3(x-1)^2-108

The x-intercepts are when y = 0

\implies 3(x-1)^2-108=0

\implies 3(x-1)^2=108

\implies (x-1)^2=36

\implies x-1=\pm \sqrt{36}

\implies x=1\pm 6

\implies x=7, x=-5

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0
3 years ago
Easyish PreCalculus; Find the exact values of the six trigonometric functions of the given angle. (you can use a calculator.) (D
Brut [27]

Answer:

there is no given angle here man

Step-by-step explanation:

5 0
3 years ago
8) The perimeter of a rectangle is 20x2 + xy - 7y2 and one of it's sides is
Sedbober [7]

Answer:

3x^2 + 3xy/2 - 7xy^2/2

Step-by-step explanation:

So we know the perimeter is 20x^2 + xy - 7y^2,

To find any perimeter you need 2l + 2w = P so,

One of the sides is 7x^2 - xy

First plug in the values,

2(7x^2-xy) + 2w = 20x^2 + xy - 7y^2

Multiply,

14x^2-2xy + 2w = 20x^2 + xy - 7y^2

Subtract,

14x^2 - 2xy - 14x^2 + 2xy + 2w = 20x^2 + xy - 7y^2 - 14x^2 + 2xy

2w = 6x^2 + 3xy - 7y^2

w = 3x^2 + 3xy/2 - 7xy^2/2

5 0
3 years ago
Which equation shows 4n = 2(+ - 3) solved for T?
Ghella [55]

Answer:

C. T = 4n+6/2

Step-by-step explanation:

4n = 2(T-3)

or, 4n = 2T-6

or, 4n + 6 = 2T

or, 4n + 6 / 2 = T

or, T = 4n + 6 / 2

5 0
2 years ago
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