Answer:
<em>Proof below</em>
Step-by-step explanation:
Let's assume a is a type 1 integer. By definition, it means we can find an integer n such that
a=3n+1
We need to prove is a type 1 integer
Expanding
If is a type 1 integer, then we should be able to find an integer m such as
Equating
solving for m
Since we know n is an integer, then the expression of m gives an integer also. Having found the required integer m, the assumption is proven
I googled it and the answer is 1,800 miles
Step-by-step explanation:
To write a polynomial in standard form, put the degree that are the greatest first
So here it would be
Remember constant are numbers that you learned back in elementary,
Numbers like 10,90,4,1,0,-3 etc.
Remember that constant are basically represented like this
For example, 10 is represented like
Since 0 is the smallest degree possible, for a polynomial, constants are the last term of a polynomial in standard form
Answer:
Option B
Step-by-step explanation:
A unit circle means radius of the circle = 1 unit
Let a terminal point on the circle is (x, y) and angle between the point P and x-axis is θ.
Center of the circle is origin (0, 0).
Therefore, ordered pair representing the terminal point will be (OP×Cosθ, OP×Sinθ) =
OP.Cosθ = 1×Cosθ =
Cosθ =
θ = , where n = integers
Similarly, OP×Sinθ = 1×Sinθ = -
Sinθ = -
θ = , where n = integer
Common value of θ will be, θ =
Option B will be the answer.
Answer:
its B
Step-by-step explanation:
Its B