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Readme [11.4K]
3 years ago
10

What is the constant of variation for the quadratic variation? 0.1y = 3x2

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

The constant of variation for the given quadratic equation is, 30

Step-by-step explanation:

One of the form of a quadratic equation is written as:

y = kx^2     ....[1]

where k is the coefficient and for this case the constant of variation.

In order to obtain the answer for the given equation, we write the given equation to the form above.

0.1y=3x^2  or

y=(\frac{3}{0.1})x^2 or

y=30x^2

Comparing this equation with equation [1], to get the value of k;

k=30.

therefore, the  constant of variation is, 30.

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Question 22.). Write the equation in Standard Form:

10y = 12x + 0.7

Identify: A, B, C

Standard Form for Linear Equation: Ax + By = C

10y = 12x + 0.7

The Standard Form of the solution is

Ax + By = C, Where, A ≥ 0

A and B, are Non- Zero numbers.

Therefore, Your answer, Letter Choice, (D), 120x - 100y = - 7, Where,

A = 120, B = - 100, and C = - 7

Question 24.). Described as, Inconsistent, Consistent, and Independent, Consistent, and Dependent, or None of These.

9x - 8y = 15, and 27x - 24y = 3

Solve:

9x - 8y = 15; 27x - 24y = 3

Steps: I will try to solve the system of equation:

9x - 8y = 15; 27x - 24y = 3

Step, Solve: 9x - 8y = 15 for x

9x - 8y + 8y = 15 + 8y

Add 8y to both sides:

9x = 8y + 15

9x/9 = 8y + 15/9 ( Divide both sides by 9):

x = 8/9y + 5/3

Step Substitute:

8/9y + 5/3 for X in 27x - 24y = 3

27x - 24y = 3

27 ( 8/9y + 5/3) - 24y = 3

45 = 3

Simplify Both sides of equation:

45 + - 45 = 3 + - 45 ( Add - 45, to both sides.):

0 = - 42

Therefore, No real Solutions, to both Equation.

Hence; 9x - 8y = 15; and 27x - 24 = 3, have No Real Solutions, and Therefore, They are, Answer Letter Choice, (B), Inconsistent.

Hope that helps!!! Sorry, I couldn't figure out Number (23.). : )

8 0
3 years ago
Homework: 5.1 Systems of Linear Equations
Klio2033 [76]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=8,\:y=5

Step-by-step explanation:

Given the system of linear equations

7x-y=51

x+3y=23

solving by the elimination method

\begin{bmatrix}7x-y=51\\ x+3y=23\end{bmatrix}

\mathrm{Multiply\:}x+3y=23\mathrm{\:by\:}7\:\mathrm{:}\:\quad \:7x+21y=161

\begin{bmatrix}7x-y=51\\ 7x+21y=161\end{bmatrix}

7x+21y=161

-

\underline{7x-y=51}

22y=110

so

\begin{bmatrix}7x-y=51\\ 22y=110\end{bmatrix}

now solving for y

22y=110

\mathrm{Divide\:both\:sides\:by\:}22

\frac{22y}{22}=\frac{110}{22}

y=5

\mathrm{For\:}7x-y=51\mathrm{\:plug\:in\:}y=5

7x-y=51

7x-5=5

7x=56

\mathrm{Divide\:both\:sides\:by\:}7

\frac{7x}{7}=\frac{56}{7}

x=8

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=8,\:y=5

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Answer:

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Step-by-step explanation:

6 0
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