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Aliun [14]
3 years ago
9

Without graphing, what can you say about the points (2.5, 1) and (6, 1) on the coordinate plane?

Mathematics
1 answer:
mars1129 [50]3 years ago
5 0

Answer:

hope this helps

Step-by-step explanation:

-they do not have the same slope

-their lines are not parallel

there's probably more but i cant quite think of it as of now

You might be interested in
A customer pays $3.27 for oranges and $4.76 for pears. How many pounds of fruit does the customer buy?
ruslelena [56]
Take 3.27 and divide that by 1.09  (for the oranges)
3.27/1.09=3lbs. of oranges
then take 4.76 and divide that by 1.19       (for the pears)
4.76/1.19=4lbs. of pears
add 4+3 to get how many lbs. in all
4+3=7

3 0
3 years ago
Doug lives 7. Block away from his school . Each block is about 265 feet long. What is total round-trip dostance,in miles that Do
olga_2 [115]

Answer:

B : 0.7

Step-by-step explanation:

Given:

Doug lives 7. Block away from his school.

Each block is about 265 feet long.

Question asked:

What is total round-trip distance,in miles that Doug walks to and from school each day ?

Solution:

Each block is about = 265 feet

7 Block = 265\times7 = 1855 \ feet

As he lives 7 block away from his school that means his round trip distance is,

7 block ( travel during going to school ) + 7 block ( when return from school )

<em>Therefore, his total round trip is 14 block, means 1855 feet + 1855 feet = 3710 feet.</em>

Now, we have to convert it into miles as here asked: (unitary method)

5280 feet = 1 mile

1 feet = \frac{1}{5280}

3710 feet = \frac{1}{5280}\times3710

               = \frac{3710}{5280} = 0.7 \ miles

Thus, total round-trip distance,in miles that Doug walks to and from school each day is 0.7 miles.

5 0
3 years ago
Can someone please help me I'm stuck on this question im in desperate need of help
kotegsom [21]

Answer:

A

Step-by-step explanation:

Point L's coordinates' difference is 7.

Point C's is 1.

Point H's is 2

And Point A's is 1

<em>Hope that helps!</em>

5 0
3 years ago
Read 2 more answers
What is the converse of the conditional statement?
dem82 [27]

Answer:

according to me 1st option seems to be correct❤️

5 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each verbal description of a sequen
galben [10]

Answer:

I think the question is wrong so, I will try and explain with some right questions

Step-by-step explanation:

We are give 6 sequences to analyse

1. an = 3 · (4)n - 1

2. an = 4 · (2)n - 1

3. an = 2 · (3)n - 1

4. an = 4 + 2(n - 1)

5. an = 2 + 3(n - 1)

6. an = 3 + 4(n - 1)

1. This is the correct sequence

an=3•(4)^(n-1)

If this is an

Let know an+1, the next term

an+1=3•(4)^(n+1-1)

an+1=3•(4)^n

There fore

Common ratio an+1/an

r= 3•(4)^n/3•(4)^n-1

r= (4)^(n-n+1)

r=4^1

r= 4, then the common ratio is 4

Then

First term is when n=1

an=3•(4)^(n-1)

a1=3•(4)^(1-1)

a1=3•(4)^0=3.4^0

a1=3

The first term is 3 and the common ratio is 4, it is a G.P

2. This is the correct sequence

an=4•(2)^(n-1)

Therefore, let find an+1

an+1=4•(2)^(n+1-1)

an+1= 4•2ⁿ

Common ratio=an+1/an

r=4•2ⁿ/4•(2)^(n-1)

r=2^(n-n+1)

r=2¹=2

Then the common ratio is 2,

The first term is when n =1

an=4•(2)^(n-1)

a1=4•(2)^(1-1)

a1=4•(2)^0

a1=4

It is geometric progression with first term 4 and common ratio 2.

3. This is the correct sequence

an=2•(3)^(n-1)

Therefore, let find an+1

an+1=2•(3)^(n+1-1)

an+1= 2•3ⁿ

Common ratio=an+1/an

r=2•3ⁿ/2•(3)^(n-1)

r=3^(n-n+1)

r=3¹=3

Then the common ratio is 3,

The first term is when n =1

an=2•(3)^(n-1)

a1=2•(3)^(1-1)

a1=2•(3)^0

a1=2

It is geometric progression with first term 2 and common ratio 3.

4. I think this correct sequence so we will use it.

an = 4 + 2(n - 1)

Let find an+1

an+1= 4+2(n+1-1)

an+1= 4+2n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=4+2n-(4+2(n-1))

d=4+2n-4-2(n-1)

d=4+2n-4-2n+2

d=2.

The common difference is 2

Now, the first term is when n=1

an=4+2(n-1)

a1=4+2(1-1)

a1=4+2(0)

a1=4

This is an arithmetic progression of common difference 2 and first term 4.

5. I think this correct sequence so we will use it.

an = 2 + 3(n - 1)

Let find an+1

an+1= 2+3(n+1-1)

an+1= 2+3n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=2+3n-(2+3(n-1))

d=2+3n-2-3(n-1)

d=2+3n-2-3n+3

d=3.

The common difference is 3

Now, the first term is when n=1

an=2+3(n-1)

a1=2+3(1-1)

a1=2+3(0)

a1=2

This is an arithmetic progression of common difference 3 and first term 2.

6. I think this correct sequence so we will use it.

an = 3 + 4(n - 1)

Let find an+1

an+1= 3+4(n+1-1)

an+1= 3+4n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=3+4n-(3+4(n-1))

d=3+4n-3-4(n-1)

d=3+4n-3-4n+4

d=4.

The common difference is 4

Now, the first term is when n=1

an=3+4(n-1)

a1=3+4(1-1)

a1=3+4(0)

a1=3

This is an arithmetic progression of common difference 4 and first term 3.

5 0
3 years ago
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