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3 years ago

I seem to be confused can anyone please help

Mathematics

1 answer:

Genrish500 [490]3 years ago

6 0

Use photo math :>some helpful info

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Determine the rate of change of the following linear equation as it translates from (-5, -1) to any other point on the line.

Norma-Jean [14]

The rate of change of a linear equation (first degree) is equivalent to the slope of a line. Slope is described as the vertical movement (rise) of the line over its horizontal counterpart (run). In determining the rate of change or slope (m) given 1 data point (x',y'), point-slope form is applicable. Point-slope form is: (y-y') = m (x-x'). Substitute the given point (-5,-1) in the equation. By substitution, [y-(-1)] = m [x-(-5)]. Re-arranging the equation, the rate of change or slope is, m = (y+1)/(x+5).

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3 years ago

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Answer:

What is

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2 years ago

15.000 at 9 percent interest

Ksivusya [100]

Answer:

$16.35

Step-by-step explanation:

15 x 1.09 = 16.35

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3 years ago

The data below are the monthly average high temperatures for New York City. What is the five-number summary? 40, 40, 48, 61, 72,

yawa3891 [41]

Answer:

B) Sample minimum: 40, Sample maximum: 84

Q1: 45, Median: 63, Q3: 77

Step-by-step explanation:

The first step is to write the temperatures in crescent order:

40, 40, 42, 48, 54, 61, 65, 72, 76, 78, 84, 84,

The sample minimum is the lowest value = 40

The sample maximum is the highest value = 84.

Since there are 12 numbers, the sample median is the average between the 6th and 7th terms:

$M = \frac{61+65}{2}\\ M=63$

The first quartile is the average between the 3rd and 4th terms:

$Q_1 = \frac{42+48}{2}\\ Q_1=45$

The third quartile is the average between the 9th and 10th terms:

$Q_3 = \frac{76+78}{2}\\ Q_3=77$

Therefore, the answer is:

B) Sample minimum: 40, Sample maximum: 84

Q1: 45, Median: 63, Q3: 77

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3 years ago

What is the horizontal asymptote of j(x) =

Korvikt [17]

Answer: y=7

Step-by-step explanation:

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3 years ago

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