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riadik2000 [5.3K]
3 years ago
12

X + 2y = 7 3x - 2y = -3

Mathematics
1 answer:
VladimirAG [237]3 years ago
4 0
Use Subtraction

1. Subtract
x+2y=7
3x-2y=-3
-------------
4x+0y=4 SIMPLIFY 4x=4

2. DIVIDE

4x=4
x=1

Substitute that into either of the original equations to get x=1, y=3





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Which expression is equivalent to r to the 9th over r to the 3rd
alisha [4.7K]

Answer:

r^{6}

Step-by-step explanation:

To make this a bit easier to see, we'll expand that expression.

R to the 9th is just r times itself 9 times. R to the third is r times itself 3 times.

(excuse my bad formatting)

<u>The expression:</u>

<u>r • r • r • r • r • r • r • r • r • 1</u>

             r • r • r • 1

Remember, anything and everything has a coefficient or denominator of 1.

So, we can cancel 3 r's from the numerator and denominator.

<u>r • r • r • r • r • r • 1</u>

             1

Simplify....

\frac{1r^{6}}{1}

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3 0
3 years ago
Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.
Bingel [31]

Answer:

\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}

Because the \lim_{x\to -\infty} \frac{1}{x} =0

The integral converges to \frac{1}{5}

Step-by-step explanation:

For this case we want to find the following integral:

\int_{-\infty}^{-5} x^{-2}dx

And we can solve the integral on this way:

\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}

\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}

And if we evaluate the integral using the fundamental theorem of calculus we got:

\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}

Because the \lim_{x\to -\infty} \frac{1}{x} =0

The integral converges to \frac{1}{5}

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Step-by-step explanation

8 0
3 years ago
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5 0
3 years ago
Research suggest that people are less likely to become repeat offenders if they stay out of the prison system. Why do you think
kondaur [170]

Answer:

Yes prison breeds criminal minds

Step-by-step explanation:

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5 0
3 years ago
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