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iVinArrow [24]
2 years ago
10

Solve for x I need help again :/

Mathematics
1 answer:
Nostrana [21]2 years ago
7 0

The Angles depicted 38° and (6x + 2)° are equal because they form vertical opposite Angle pair.

so,

  • 6x + 2 = 38

  • 6x = 38 - 2

  • 6x = 36

  • x = 36 ÷ 6

  • x = 6
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Use the simple interest formula to solve.
xxTIMURxx [149]
The formula of simple interest to find the amount
principal plus simple interest
p+si=a

the formula to find the simple interest
principle multiplied by rate of interest multiplied by time the whole divided by 100
p*r*t/100=si

let us replace the formula
43500*2.25*5/100=si
97875*5/100=si
489375/100=si
4893.75=si

4893.75+43500=a
48393.75=a
hope you found this useful
please put this as the brainliest answer please
4 0
3 years ago
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A bulletin board is 3ft high, it's area is 15 square ft what is the perimeter of the bulletin board
Molodets [167]
16 Feet because 15 divided by 3 is 5 then you add 3+3+5+5
3 0
3 years ago
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3 2/3 + 2.3 (the three is repeating) and the answer choices are
Ne4ueva [31]

Step-by-step explanation:

please check and rewrite ur question

7 0
3 years ago
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Help please urgent 25 point
uranmaximum [27]

Answer:

60

Step-by-step explanation:

b = the hypotenuse of a right angle triangle

a = the adjacent side.

R is being defined by the cosine

cos(R) = adjacent /  hypotenuse

adjacent = 16* sqrt(2)

hypotenuse = 32*sqrt(2)

Cos(R) = 16*sqrt(2) / 32*sqrt(2)      sqrt(2) cancels.

cos(R) = 1/2

R = cos-1(1/2)

R = 60 degrees.

4 0
3 years ago
HELP ASAP PLEASE.
nordsb [41]
The range of the primary phone data is 0.28. 
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.

To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28

To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73

To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12

To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6

The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
5 0
3 years ago
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