So first we need to find what percent of the students walk to school.
50 + 35 = 85% don't walk leaving only 15% that walk to school,
To find the 15% percent that DO walk we multiply .15 by the total number of people.
.15 x 1640 = 246 people walk to school
Answer:
y=3x+2
Step-by-step explanation:
3x - y = -2
-3x -3x
_________
-y = -3x-2
/-1 /-1
_________
y = 3x+2
Answer:
3350
Step-by-step explanation:
100 + 8 = 108%
108% is 3618
100% is x
108x = 3618 * 100
108x = 361800
x = 361800/108
= 3350
Hence, the original salary is HRK 3350
<em>Feel free to mark this as brainliest! :D</em>
Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean salary of all graduates from the English department.
Number of sample, n = 400
Mean, u = $25,000
Standard deviation, s = $2,500
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z × standard deviation/√n
It becomes
25000 ± 1.96 × 2500/√400
= 25000 ± 1.96 × 125
= 25000 ± 245
The lower end of the confidence interval is 25000 - 245 =24755
The upper end of the confidence interval is 25000 + 245 = 25245
Therefore, with 95% confidence interval, the mean salary of all graduates from the English department is between $24755 and $25245
A sample is a small subset of a population, on which startistical analysis is carried out to obtain the characteristics of the population.
Sampling is the process of selecting units (e.g., people, organizations) from a
population of interest to obtain the characteristics of the population.
When drawing a sample, it is important that all the components of the population of interest is adequately represented.
Thefollowing samples are categorised based on whether they fairly represent the population of interest or not.
1.) M<span>easuring the heights of every fiftieth person on the school roster to determine the average heights of the boys in the school.
Here, the population of interest is the boys in the school. Drawing a sample of every fiftieth person on the school roster will contain both boys and girls whereas girls are not needed for the purpose of the survey.
Threfore, the sample does not represent fairly the population of interest.
2.) C</span><span>alling
every third person on the soccer team’s roster to determine how many of
the team members have completed their fundraising assignment.
Here, the population of interest is the team members, so drawing a sample of every third person on the soccer team's roster represents fairly the population of interest.
3.) </span>O<span>bserving every person walking down Main Street at 5 p.m. one evening to determine the percentage of people who wear glasses.
Here the population of interest is people who wear glasses, though observing people walking down the road might be a good way to drawing this sample, but the sample will be biased because by 5 pm, the sum will be down and the people who wear glasses because of the sun might not have their glasses on again.
So this sample does not fairly represent the population of interest.
4.) </span>Sending
a confidential e-mail survey to every one-hundredth parent in the
school district to determine the overall satisfaction of the residents
of the town.
Here, the population of interest is the residents of the town and not all residents of the town might be a parent.
So, the sample of one-hundredth parent in the school district does not fairly represent the population of interest.
5.) T<span>aking
a poll in the lunch room (where all students currently have to eat
lunch) to determine the number of students who want to be able to leave
campus during lunch.
Here, the population of interest is the students and taking a poll in the lunch room (where all students currently have to eat lunch) fairly represent the population of interest.
Therefore, the samples that fairly represent the population are:
</span>
<span>C<span>alling
every third person on the soccer team’s roster to determine how many of
the team members have completed their fundraising assignment.
and
</span></span>T<span>aking
a poll in the lunch room (where all students currently have to eat
lunch) to determine the number of students who want to be able to leave
campus during lunch.</span>
