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VladimirAG [237]
3 years ago
7

If a circular cross-section with a center at (1, 1) and radius of 1 is rotated about the line y = 1, what will be the resulting

three-dimensional object?

Mathematics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

sphere (see the explanation)

Step-by-step explanation:

we know that

When you will rotate a circle about its diameter, you will obtain a sphere.

The radius of the sphere will the same as that of the circle.

In this problem

The circle is rotated about the line y=1

The line y=1 passes through a diameter of the circle

The equation of the circle is

(x-1)^2+(y-1)^2=1

see the attached figure to better understand the problem

so

The circle is rotated about its diameter

therefore

The resulting three-dimensional object will be a sphere with radius of 1

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edited Mar 6 '17 at 4:38

Richard Ambler

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asked Mar 6 '17 at 3:34

14wml

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Add a comment

1 Answer

1

No. It is not true that =cos()+sin(). Notice that

1=1≠cos()+sin(),

for example consider this at =0.

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+=ln(+)

then recall your rules for logarithms to get this to the form (+)ln().

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Sum of angles around a point = 360

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The actual area of the lawn is 2940ft^2

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