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VladimirAG [237]
3 years ago
7

If a circular cross-section with a center at (1, 1) and radius of 1 is rotated about the line y = 1, what will be the resulting

three-dimensional object?

Mathematics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

sphere (see the explanation)

Step-by-step explanation:

we know that

When you will rotate a circle about its diameter, you will obtain a sphere.

The radius of the sphere will the same as that of the circle.

In this problem

The circle is rotated about the line y=1

The line y=1 passes through a diameter of the circle

The equation of the circle is

(x-1)^2+(y-1)^2=1

see the attached figure to better understand the problem

so

The circle is rotated about its diameter

therefore

The resulting three-dimensional object will be a sphere with radius of 1

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What survival rate in the 10th year would make the average rate of loss over the 10-year period equal to 38.0%?
Morgarella [4.7K]

Answer: 63%

Step-by-step explanation:

First find the rate of loss that would cause the average rate of loss over the 10-year period equal to 38.0%.

Assume that rate is x.

38 = (36.2 + 29.0 + 46.2 + 37.5 + 40.9 + 40.0 + 32.6 + 40.5 + 40.1 + x) / 10

38 = (343 + x ) / 10

380 = 343 + x

x = 380 - 343

x = 37%

The survival rate is the opposite of the rate of loss which means that the survival rate is;

= 1 - rate of loss

= 1 - 37%

= 63%

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.......................................................
valkas [14]
Hope this helps lol :)

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Find to the nearest tenth the radian meausure of 216 degrees.
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