If a circular cross-section with a center at (1, 1) and radius of 1 is rotated about the line y = 1, what will be the resulting
three-dimensional object?
1 answer:
Answer:
sphere (see the explanation)
Step-by-step explanation:
we know that
When you will rotate a circle about its diameter, you will obtain a sphere.
The radius of the sphere will the same as that of the circle.
In this problem
The circle is rotated about the line y=1
The line y=1 passes through a diameter of the circle
The equation of the circle is
see the attached figure to better understand the problem
so
The circle is rotated about its diameter
therefore
The resulting three-dimensional object will be a sphere with radius of 1
You might be interested in
In accordance with <em>propositional</em> logic, <em>quantifier</em> theory and definitions of <em>simple</em> and <em>composite</em> propositions, the negation of a implication has the following equivalence:
(Correct choice: iii)
<h3>How to find the equivalent form of a proposition</h3>
Herein we have a <em>composite</em> proposition, that is, the union of <em>monary</em> and <em>binary</em> operators and <em>simple</em> propositions. According to <em>propositional</em> logic and <em>quantifier</em> theory, the negation of an implication is equivalent to:
To learn more on propositions: brainly.com/question/14789062
#SPJ1