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VladimirAG [237]
3 years ago
7

If a circular cross-section with a center at (1, 1) and radius of 1 is rotated about the line y = 1, what will be the resulting

three-dimensional object?

Mathematics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

sphere (see the explanation)

Step-by-step explanation:

we know that

When you will rotate a circle about its diameter, you will obtain a sphere.

The radius of the sphere will the same as that of the circle.

In this problem

The circle is rotated about the line y=1

The line y=1 passes through a diameter of the circle

The equation of the circle is

(x-1)^2+(y-1)^2=1

see the attached figure to better understand the problem

so

The circle is rotated about its diameter

therefore

The resulting three-dimensional object will be a sphere with radius of 1

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1/x + 1/3x =6 how do you solve this equation for x
Elodia [21]

Answer:

x = 2/9 (or = 0.222)

Step-by-step explanation:

1/x + 1/(3x) =6  (multiply both sides by 3x)

(1/x) (3x)  + [1/(3x)](3x) =6 (3x)

3 + 1 = 18x

4 = 18x

x = 4/18

x = 2/9 (or = 0.222)

3 0
3 years ago
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dybincka [34]
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(Picture) MULTIPLYING POLYNOMIALS AND SIMPLIFYING EXPRESSIONS PLEASE HELP!!!!
kvv77 [185]

Answer:

Answer: Third option is the right answer.

Step-by-step explanation:

First we the write the expression

(a+b)(a^{2}+b^{2}-ab)

Now teacher says that the product of these polynomials will result in the sum of  a^{3}+b^{3}

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3 0
3 years ago
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yuradex [85]

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3 0
3 years ago
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8_murik_8 [283]

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