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Anit [1.1K]
2 years ago
15

What survival rate in the 10th year would make the average rate of loss over the 10-year period equal to 38.0%?

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
7 0

Answer: 63%

Step-by-step explanation:

First find the rate of loss that would cause the average rate of loss over the 10-year period equal to 38.0%.

Assume that rate is x.

38 = (36.2 + 29.0 + 46.2 + 37.5 + 40.9 + 40.0 + 32.6 + 40.5 + 40.1 + x) / 10

38 = (343 + x ) / 10

380 = 343 + x

x = 380 - 343

x = 37%

The survival rate is the opposite of the rate of loss which means that the survival rate is;

= 1 - rate of loss

= 1 - 37%

= 63%

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2 years ago
Type the correct answer for each.
xxTIMURxx [149]
If point \left(x,\ \frac{\sqrt{7}}{3}\right) is on the unit ircle, then:

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Since, the point is in the second quadrant, x is negative.

Thus, (x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)

Part A:

3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\  \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\  \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\  \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta

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Part B:

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8 0
3 years ago
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Step-by-step explanation:

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5 0
1 year ago
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The complete question in the attached figure

Part a) 
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the answer part a) is
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height=6 cm
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the answer part b) is 
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