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Scorpion4ik [409]

3 years ago

6

At a jeans factory, a random quality check found 8 pairs defective and 292 pairs with no problems. How many defective pairs can

be expected in the inventory of 3,000 pairs of jeans?

2 answers:

Soloha48 [4]3 years ago

8 0

Answer:

82

Step-by-step explanation:

8- defective

292- no problems

300- total

defective every 1/36.5

3000/ 36.5 = 82

12345 [234]3 years ago

7 0

<span>57/6 = 9.5... 9.5 * 8 = 76 </span>

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What method would be best to use 53=4(x-3)^2-11

Veronika [31]

Answer:

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Step-by-step explanation:

<u>SOLUTION :-</u>

$4(x-3)^2-11 = 53$

Add 11 to both the sides.

$=> 4(x-3)^2-11+11=53+11$

$=> 4(x-3)^2 = 64$

Divide both the sides by 4.

$=> \frac{4(x-3)^2}{4} = \frac{64}{4}$

$=> (x-3)^2 = 16$

Root square both the sides.

$=> \sqrt{(x-3)^2} = \sqrt{16}$

$=> x-3 = +4 \; or -4$

Here , x will have two values -

1) $x-3 = 4$

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2) $x - 3 = -4$

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<u>VERIFICATION :-</u>

When x = 7 ,

$4(x-3)^2 - 11 = 4(7 - 3)^2 - 11$

$= 4 \times 4^2 - 11$

$= 4 \times 16 - 11$

$= 64 - 11$

$= 53$

When x = -1 ,

$4(x-3)^2 - 11 = 4(-1 - 3)^2 - 11$

$= 4 \times (-4)^2 - 11$

$= 4 \times 16 - 11$

$= 64 - 11$

$= 53$

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