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iragen [17]
2 years ago
5

I just subscribed and it’s not what I thought. How do I cancel and get refund without going through my bank?

Mathematics
2 answers:
OLga [1]2 years ago
8 0

Answer:

that's tuff

Step-by-step explanation:

unf9rtunate and nluky

Reptile [31]2 years ago
5 0
I think there’s no refund once you purchase something but I think u can cancel your subscription in apple store or play store
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The equation of a parabola changes from y = x2 − 2 to y = x2 + 5. What transformation best describes the change in the equation?
Gwar [14]
I'm not totally sure the exact answer, or if this even helps, but the Y intercept is changing from -2 to 5
7 0
3 years ago
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How does the value represented by the digit 4 in R compare to the value represented by the digit 4 in T?
timurjin [86]

Answer:

69x

Step-by-step explanation:

4 0
3 years ago
The volume of this rectangular solid is?
Maru [420]

Well, volume is: length x width x height


so, 5 x 14 x 8= 560 inches

8 0
3 years ago
Question 5 and 6 please help me
sp2606 [1]

Problem 5

The function is continuous for the given domain x \ge 6

This is because y = (-5/6)x+5 is itself continuous, and any interval subset of this function is also continuous. We can plug in any real number that is equal to 6 or larger, and get some y output. If we plugged in x = 6, then we'd get

y = (-5/6)x+5

y = (-5/6)*6 + 5

y = -5+5

y = 0

This is the largest y value possible. Why? Because y = (-5/6)x+5 has a negative slope, so the graph is going downhill as you read it from left to right. As x gets bigger, y gets smaller. The smallest x value allowed in the domain produces the largest y value in the range. There is no smallest y value as the y values keep going down forever.

The range is therefore y \le 0

In interval notation, you can write the range as (-\infty, 0]. The square bracket indicates "include this endpoint as part of the range".

======================================================

Problem 6

The function is discrete for this given domain. The domain itself is a discrete list of values. We cannot plug in values between say 0 and 2. We can only substitute one of those values from the list given. Consequently, the y values will also be a list, and not an interval like problem 5 had.

-----------

If you plugged in x = -4, then you should get...

y = (-1/2)*(-4)+2

y = 2+2

y = 4

So the input x = -4 lead the output y = 4

Repeat for x = -2

y = (-1/2)x+2

y = (-1/2)*(-2)+2

y = 1+2

y = 3

and the same for x = 0 as well

y = (-1/2)x+2

y = (-1/2)*0 + 2

y = 0 + 2

y = 2

and x = 2 also

y = (-1/2)x+2

y = (-1/2)*2 + 2

y = -1+2

y = 1

Finally, plug in x = 4

y = (-1/2)x+2

y = (-1/2)*4+2

y = -2+2

y = 0

---------------

If we plugged each of these x values {-4, -2, 0, 2, 4} one at a time into the equation y = (-1/2)x+2, then we get this list of values {4, 3, 2, 1, 0}

Sorting the values from smallest to largest, we have this range {0, 1, 2, 3, 4}

3 0
3 years ago
How do you use distributive property on s+0.08s?
Ivanshal [37]

Answer:

s(1+.08)

Step-by-step explanation:

Each term is divisible by s, so that means we can divide them by s, which we get 1+.08, therefore getting s(1+.08) (or s(1.08)).

7 0
3 years ago
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