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3 years ago

How many times does 44 go into 1146

Mathematics

2 answers:

pychu [463]3 years ago

5 0

1146/44 = 26.045...
= 26

Feliz [49]3 years ago

4 0

I would think 26.0454545

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Four times a number x is at least 16

Angelina_Jolie [31]

Answer:

Step-by-step explanation:

4x=16

x=4

7 0

3 years ago

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What is the value of x in the equation , when y = 3?

kow [346]

Answer:

-∞ <=x<=∞

(Any value from -∞ to ∞)

Step-by-step explanation:

When y = 3,

x can be any value between -infinite to infinite

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3 years ago

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How are terminating decimals different from repeating decimals

Nady [450]

Hi. The difference between terminating decimals and different from repeating decimals is:

Terminating decimals is a decimal that ends. It is a decimal with an infinite number of digits.

Repeating decimals have a digit or a block of digits that repeat over and over again.

Hope this helps.

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8 0

4 years ago

Apolicy requiring all hospital employees to take lie detector tests may reduce losses due to theft, but some employees regard su

galina1969 [7]

suppose that any pair of tests are independent. What is the probability that a machine will conclude that

a each of three employees is lying when all are telling the truth?

b at least one of the three employees is lying when all are telling the truth?

Answer:

a. The probability that each of three employees is lying when all are telling the truth is 0.000125

b. The probability that at least one of the three employees is lying when all are telling the truth is 0.1426

Step-by-step explanation:

Let the event be;

A= the lie detector concludes that a person is lying who, in fact, is telling the truth

B= the lie detector concludes that a person is lying who, in fact, is telling lie

Given their probabilities as:

P(A)= 0.05 and P(B)= (1 - 0.05)= 0.95

a. What is the probability that a machine will conclude that each of three employees is lying when all are telling the truth?

A binomial problem with n= 3 and P= 0.05

P(all are telling truth) = P^n= 0.05^3 = 0.000125

b. What is the probability that at least one of the three employees is lying when all are telling the truth?

P(at least one is telling) = P(one is telling lie) + P(two are telling lie) + P(three are telling lie)

P(at least one is telling) = 1 - P(B) = 1 - (0.95)^3 = 0.1426

4 0

4 years ago

Given f(x)=x^2+2x+3 and g(x)=x+4/3 solve for f(g(x)) when x=2

Makovka662 [10]

Answer:

$\displaystyle\mathsf{f(g(2)) \:=\:\frac{187}{9}}$

Step-by-step explanation:

We are provided with the following functions:

f(x) = x² + 2x + 3

$\displaystyle\mathsf{ g(x)\:=\:x+\frac{4}{3} }$

The given problem also requires to find the Composition of Functions, f(g(x)) when x = 2.

The <u>Composition of Function</u> <em>f</em> with function <em>g</em> can be expressed as ( <em>f ° g </em>)(x) = f(g(x)). In solving for the composition of functions, we must first evaluate the <em>innermost</em> function, g(x), then use the output as an input for f(x).

<h2>Solve for f(g(x)) when x = 2:</h2><h3><u>Find g(x):</u></h3>

Starting with g(x), we will use x = 2 as an <u>input</u> value into the function:

$\displaystyle\mathsf{ g(x)\:=\:x+\frac{4}{3} }$

$\displaystyle\mathsf{ g(2)\:=\:(2)+\frac{4}{3} }$

Transform the first term, x = 2, into a fraction with a denominator of 3 to combine with 4/3:

$\displaystyle\mathsf{ g(2)\:=\:\frac{2\: \times\ 3}{3}+\frac{4}{3} }$

$\displaystyle\mathsf{ g(2)\:=\:\frac{6}{3}+\frac{4}{3}\:=\:\frac{6+4}{3}}$

$\displaystyle\mathsf{ g(2)\:=\:\frac{10}{3} }$

$\displaystyle\mathsf{Therefore,\:\: g(2)\:=\:\frac{10}{3} }$

Next, we will use $\displaystyle\mathsf{\frac{10}{3}}
$ as input for the function, f(x) = x² + 2x + 3:

f(x) = x² + 2x + 3

$\displaystyle\mathsf{f\Bigg (\frac{10}{3}\Bigg)\:=\:x^2 \:+ 2x\:+\:3}$

$\displaystyle\mathsf{f\Bigg (\frac{10}{3}\Bigg) \:=\:\Bigg (\frac{10}{3}\Bigg)^{2}\:+ 2\Bigg(\frac{10}{3}\Bigg) \:+\:3}$

Use the <u>Quotient-to-Power Rule of Exponents</u> onto the <em>leading term </em>(x²):

$\displaystyle\mathsf{Quotient-to-Power\:\:Rule:\:\: \Bigg(\frac{a}{b}\Bigg)^m\:=\:\frac{a^m}{b^m} }$

$\displaystyle\mathsf{f\Bigg (\frac{10}{3}\Bigg) \:=\:\Bigg (\frac{10\:^2}{3\:^2}\Bigg)\:+ 2\Bigg(\frac{10}{3}\Bigg) \:+\:3}$

Multiply the numerator (10) of the middle term by 2:

$\displaystyle\mathsf{f\Bigg (\frac{10}{3}\Bigg) \:=\:\Bigg (\frac{100}{9}\Bigg)\:+ \Bigg(\frac{20}{3}\Bigg) \:+\:\frac{3}{1}}$

Determine the <u>least common multiple (LCM)</u> of the denominators from the previous step: 9, 3, and 1 (which is 9).
Then, transform the denominators of 20/3 and 3/1 on the <u>right-hand side</u> of the equation into like-fractions:

$\displaystyle\mathsf{\frac{20}{3}\Rightarrow \:\frac{20\:\times\ 3}{3\:\times\ 3} =\:\frac{60}{9}}$