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hjlf
3 years ago
14

On February 1, a seller paid $1,140 in annual property tax for the current calendar year. He sold the house with the closing set

for April 1. What will be the seller's credit for the property taxes already paid if the buyer pays for the day of closing?
Business
1 answer:
tigry1 [53]3 years ago
6 0

Answer:

$288

Explanation:

Since the total property taxes for the year are $1,140, to find the property tax per month we have to divide by 12 ⇒ $1,140 / 12 = $95 per month

The seller is responsible for paying the property taxes during 3 months and 1 day, to find out the amount for that 1 day we divide the monthly tax by 30 = $3.17 per day.

the total seller's credit = ($95 x 3) + $3 = $285 + $3 = $288

*The seller's credit includes all the expenses that must be paid by the seller, while the seller's debit includes all the money that he receives.

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3 years ago
If investors expect a total return of 14.60%, what will be Goodwin’s expected dividend and capital gains yield in two years—that
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Answer:

First Expected Dividend will come in at the end of Year 3 or t=3 assuming current time is t=0.

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Therefore, Current Stock Price = Present Value of Expected Dividends = [6.59459 / (0.136-0.0408)] x [1/(1.136)^(5)] + 4.25 / (1.136)^(3) + 5.18925 / (1.136)^(4) + 6.33607 / (1.136)^(5) = $ 45.979 ~ $ 45.98

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7 0
4 years ago
A car dealer who sells only late-model luxury cars recently hired a new salesman and believes that this salesman is selling at l
Natasha2012 [34]

Answer:

t=\frac{5000-5600}{\frac{800}{\sqrt{16}}}=-3      

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Data given and notation      

\bar X=5000 represent the sample mean      

s=800 represent the standard deviation for the sample      

n=16 sample size      

\mu_o =5600 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean is lower than 5600, the system of hypothesis would be:      

Null hypothesis:\mu \geq 5600      

Alternative hypothesis:\mu < 5600      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

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Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{5000-5600}{\frac{800}{\sqrt{16}}}=-3      

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