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Mekhanik [1.2K]
3 years ago
8

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0

Answer:

\displaystyle \boxed{2x^2 - x + 1}

Step-by-step explanation:

Since the divisor of \displaystyle x + 1is in the form of \displaystyle x - c,use what is called Synthetic Division. Remember, in this formula, −c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

−1| 2 1 0 1

↓ −2 1 −1

__________

2 −1 1 0 → \displaystyle 2x^2 - x + 1

You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [2x³ + x² + 1]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than the leading coefficient of your dividend, so that 2 in your quotient can be a 2x², the −x follows right behind it, and bringing up the rear, 1, giving you the quotient of 2x² - x + 1.

I am joyous to assist you anytime.

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kotegsom [21]

Answer:

As the input increases, the output decreases for all values of x.

Step-by-step explanation:

The function is linear (a straight line) which heads down and to the right. There is no asymptote stopping the function from decreasing.

Formally, the behavior is described like so: as x approaches infinity, f(x) decreases

6 0
3 years ago
Please answer the following, 50 points available!
Rus_ich [418]

Answer for Area:

6,518.75 square meters

Explanation for Area:

First, you would multiply the length and the width of the car park to find its area (75 x 100 =7500). Now, find the area of the arena. Since you are given the diameter, divide it by 2 to get the radius (25). Now multiply π by 25^2. This should give you 1962.5. Then, since only half of the arena is in the car park, divide the area of the arena by 2. Now you have 981.25. Now, subtract this from the area of the car park (7500). Your answer should now be 6,518.75.

Answer for Fence:

295 meters

Explanation for Fence:

Add up all the sides. There are two sides with 100 meters and 2 sides with 75 meters. But, because you arent supposed to include the space where the arena is. only add 25. This gets you 300. Now, subtract 5 meters for a gate. 295 is your final answer.

6 0
3 years ago
Read 2 more answers
Gravel is being dumped from a conveyor belt at a rate of 15 ft3/min, and its coarseness is such that it forms a pile in the shap
gayaneshka [121]

Answer:

0.13 ft/min

Step-by-step explanation:

We are given that

\frac{dV}{dt}=15ft^3/min

We have to find the increasing rate of change of height of pile  when the pile is 12 ft high.

Let d be the diameter of pile

Height of pile=h

d=h

Radius of pile,r=\frac{d}{2}=\frac{h}{2}

Volume of pile=\frac{1}{3}\pi r^2 h=\frac{1}{12}\pi h^3

\frac{dV}{dt}=\frac{1}{4}\pi h^2\frac{dh}{dt}

h=12 ft

Substitute the values

15=\frac{1}{4}\pi(12)^2\frac{dh}{dt}

\frac{dh}{dt}=\frac{15\times 4}{\pi(12)^2}

\frac{dh}{dt}=0.13ft/min

7 0
3 years ago
HELP ME PLEASE I NEED ANSWERS REALLY FAST I'LL GIVE BRAINLIEST TO THE CORRECT ANSWER SO PLEASE HELP ME!!!!
inessss [21]

Correct answers in reasoning and statements together.

Please give brainliest thank you so much!!

Hope this helps!!

4 0
2 years ago
Read 2 more answers
Find the volume of a trough 5 meters long whose ends are equilateral triangles, each of whose
yawa3891 [41]

Answer:

V=5\sqrt{3}\ m^3

Step-by-step explanation:

we know that

The volume of a trough is equal to

V=BL

where

B is the area of equilateral triangle

L is the length of a trough

step 1

Find the area of  equilateral triangle B

The area of a equilateral triangle applying the law of sines is equal to

B=\frac{1}{2} b^{2} sin(60\°)

where

b=2\ m

sin(60\°)=\frac{\sqrt{3}}{2}

substitute

B=\frac{1}{2}(2)^{2} (\frac{\sqrt{3}}{2})

B=\sqrt{3}\ m^{2}

step 2

Find the volume of a trough

V=BL

we have

B=\sqrt{3}\ m^{2}

L=5\ m

substitute

V=(\sqrt{3})(5)

V=5\sqrt{3}\ m^3

3 0
3 years ago
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