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Alona [7]
3 years ago
6

Which number line represents the solution set for the inequality 2x – 6 ≥ 6(x – 2) + 8? A number line from negative 1.5 to 1.5 i

n increments of 0.5. A point is at 0.5 and a bold line starts at 0.5 and is pointing to the left. A number line from negative 1.5 to 1.5 in increments of 0.5. A point is at 0.5 and a bold line starts at 0.5 and is pointing to the right. A number line from negative 1.5 to 1.5 in increments of 0.5. A point is at negative 0.5 and a bold line starts at negative 0.5 and is pointing to the left. A number line from negative 1.5 to 1.5 in increments of 0.5. A point is at negative 0.5 and a bold line starts at negative 0.5 and is pointing to the right.

Mathematics
2 answers:
Nuetrik [128]3 years ago
8 0

Answer:

A point is at negative 0.5 and a bold line starts at negative 0.5 and is pointing to the left.

The number line in Option C.

Step-by-step explanation:

We are given an inequality.

2x - 6 \geq 6(x - 2) + 8

We have to find the number line that shows the solution for the given inequality.

If we solve the given inequality,

2x - 6 \geq 6(x - 2) + 8\\\Rightarrow 2x - 6 \geq 6x - 12 + 8\\ \Rightarrow 2x - 6 \geq 6x - 4\\\Rightarrow 2x - 6x \ geq -4 + 6\\\Rightarrow -4x \geq 2\\\Rightarrow -x \geq 0.5\\\Rightarrow x \leq -0.5

is the required solution of the given inequality.

Thus, if we want to plot or show this solution on a number line, then we need to we need to mark the point -0.5 and all the numbers less than -0.5

A point is at negative 0.5 and a bold line starts at negative 0.5 and is pointing to the left.

This s represented in Option C.

ladessa [460]3 years ago
4 0

Answer:

C

Step-by-step explanation:

i got it right on edge

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7 0
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Read 2 more answers
Can anyone help me find the coordinates (?,?) given that the shape is a parallelogram? (15 points)
xxTIMURxx [149]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Diagonals of the parallelogram bisect each other.

Solve using mid-point formula:

$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right  )

Here x_1=m, y_1=n, x_2=h, y_2=0

              $=\left( \frac{m+h}{2}, \frac{n+0}{2}\right  )

$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right  )

<u>To find the missing coordinate:</u>

Let the missing coordinates by x and y.

Here x_1=0, y_1=0, x_2=x,  y_2=y

$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{x}{2}, \frac{y}{2}\right  )

Now equate the x-coordinate.

$ \frac{m+h}{2}=\frac{x}{2}

Multiply by 2 on both sides of the equation, we get

m + h = x

x = m + h

Now equate the y-coordinate.

$\frac{n}{2} =  \frac{y}{2}

Multiply by 2 on both sides of the equation, we get

n = y

y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

5 0
3 years ago
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