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Kryger [21]
4 years ago
13

From 2006 to 2010, the population of a town declined to 22,000. The population is expected to continue to decline at a rate of 2

.8% each year.
20 POINTS PLEASE HELP
What will the population be in 2040?

Round to the nearest whole number.



Enter your answer in the box.
Mathematics
2 answers:
Archy [21]4 years ago
6 0

i took the test and the answer was 9384


VashaNatasha [74]4 years ago
6 0

Answer: 9384

========================================

In the year 2010, the population is P = 22000 which is the starting population. The rate is r = -0.028 indicating a decrease of 2.8% annually

A = P*(1+r)^t

A = 22000*(1+(-0.028))^t

A = 22000*(1-0.028)^t

A = 22000*(0.972)^t

Now plug in t = 30 to compute the population in the year 2040 (which is 30 years after 2010)

A = 22000*(0.972)^30

A = 22000*0.42656768

A = 9384.48896

A = 9384 .... rounding to the nearest whole number

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Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

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S = \{1,1,2,2,2,3\}

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P(3) = \frac{n(3)}{n(s)}

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P(Odd Number) is then calculated as:

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P(Odd\ Number) = \frac{2+1}{6}

P(Odd\ Number) = \frac{3}{6}

P(Odd\ Number) =  \frac{1}{2}

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

S = \{1,1,2,2,2,3,3\}

The probability of each is:

P(1) = \frac{n(1)}{n(s)}

P(1) = \frac{2}{7}

P(2) = \frac{n(2)}{n(s)}

P(2) = \frac{3}{7}

P(3) = \frac{n(3)}{n(s)}

P(3) = \frac{1}{7}

P(Odd\ Number) = P(1) + P(3)

P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}

Take LCM

P(Odd\ Number) = \frac{2+1}{7}

P(Odd\ Number) = \frac{3}{7}

Comparing P(Odd Number) before and after

P(Odd\ Number) =  \frac{1}{2} --- Before

P(Odd\ Number) = \frac{3}{7} --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

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