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3 years ago

Which quadratic function is represented by the table?

Mathematics

2 answers:

Digiron [165]3 years ago

7 0

Answer: is 3x^2 - 2x + 5 on edg. your welcome jit.

Step-by-step explanation:

zzz [600]3 years ago

6 0

The answer is 3x^2 - 2x + 5.

Step-by-step explanation:

The value of x is given by f(x), the quadratic equation is given by:

3x^2 - 2x + 5

Substituting all the values of x in the equation

If x = -2 in the quadratic equation , 3x^2 - 2x + 5

3(-2)^2 - 2(-2) + 5

3(4) + 4 + 5 = 21

Again, substituting x= -1 in the same equation, we have

3(-1)^2 - 2(-1) + 5

3 + 2 + 5 = 10

Putting x=0,

3(0)^2 - 2(0) + 5 = 0

Putting x=1,

3(1)^2 - 2(1) + 5

3 - 2 + 5 = 6

Putting x=2,

3(2)^2 - 2(2) + 5

3(4) - 4 + 5 = 13

Hence, the quadratic equation which is represented by the table is

3x^2 - 2x + 5

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Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on

Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

If he is given with two kings.
If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by = $\frac{^{3}C_2 }{^{47}C_2}$ {∵ one king is already there}

= $\frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}$ {∵ $^{n}C_r = \frac{n!}{r! \times (n-r)!}$ }

= $\frac{3}{1081}$ = 0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by = $\frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}$

= $\frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}$

= $\frac{6}{1081}$ = 0.0055

Now, probability that he ends up with a full house = $\frac{3}{1081} + \frac{6}{1081}$

= $\frac{9}{1081}$ = 0.0083.

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3 years ago

Read 2 more answers

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Step-by-step explanation:

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2 years ago

Ivy randomly surveys students in her school to learn about mobile phone password use. Of 25 respondents 14 use a password. Based

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14/25 = x/275

25 => 275

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3 years ago

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Bella earned the federal minimum wage in the year 2008. During that time, she worked 37.5 hours per week. How much money did she

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Answer:

Belle's weekly earnings per week in 2008: $245.7

Step-by-step explanation:

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She worked 37.5 hours per week.

She earn each week:

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2 years ago

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Students are making ornaments and each takes 1 2 of a piece of Bristol board. They go to the cupboard and find 1 1 2 pieces of B

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Answer: 3

Step-by-step explanation:

Feom the question, we are informed that students are making ornaments and each takes 1/2 of a piece of Bristol board and that they go to the cupboard and find 1 1/2 pieces of Bristol board.

The number of ornaments that they can make will be calculated by dividing 1 1/2 by 1/2. This will be:

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= 3/2 ÷ 1/2

= 3/2 × 2/1

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2 years ago