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gregori [183]
3 years ago
15

John is about to roll a six-sided, fair number cube 60 times. He wants to predict how many times the cube will land on an even n

umber. He makes a prediction of 20 times. Is it a good prediction? What would your prediction be based on theoretical probability?
Mathematics
2 answers:
CaHeK987 [17]3 years ago
5 0

A number cube has 3 even numbers. Each even number has a theoretical probability of 1/6. In 60 rolls, an even number could come up ten times. Since there are 3 even numbers, the total predicted value is 30. So 20 is a low prediction.


Juli2301 [7.4K]3 years ago
4 0
Even numbers
so each dice has numbers
1,2,3,4,5,6
the eve numbers are
2,4,6
odd are others
1,3,5
so 1/2 are odd

therefor 1/2 of 60 is how many times it would get even
1/2 of 60=1/2 times 60=30

No not good predicition
my prediction would be 30 tiemes

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Which of the following correctly names a side of the triangle below?
slamgirl [31]

Answer:

C. \frac{}{AB}

Step-by-step explanation:

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This is how we solve this question by using the eliminating process.

(A. ∠C) is not the right answer because the ∠ sign lets us know that this answer represents an angle, not a line

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4 0
3 years ago
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Tresset [83]

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7 0
3 years ago
PLZ HEEEELP!!!!! 10 POINTS!!!!
katrin2010 [14]

Answer:

Step-by-step explanation:

Part a

We need two inequalities, one for time worked at each job and the other

for amounts of money earned.

time:  Let b and c represent the time (number of hours) worked at babysitting and landscaping respectively.  Then b + c ≤ 20 hrs/wk

earnings:  Let ($3/hr)(b) represents the amount of money earned babysitting for b hour.  Let  ($7/hr)(c) represent the money earned working at landscaping.  These amounts are <em>per week</em>.  The appropriate inequality is  ($3/hr)(b) +  ($7/hr)(c) ≥ $84 per week.  The other inequality is

b + c ≤ 20 hrs/wk.

Part b:

As before, b + c ≤ 20 hrs/wk.  What happens if Chet spends all his 20 hours babysitting?  To answer this, set c = 0 (no landscaping hours).  Then b ≤ 20 hours.  At $3/hr, he could earn only $60 and have no time left for landscaping.  Not good.

Let's experiment:  suppose he works 15 hours babysitting and 5 hours landscaping.  His earnings would be $45 + $35, or $80.  Still not enough; he wants to earn $84 total.    Let's redistribute his time and try again:  suppose he works 14 hours babysitting and 6 hours landscaping; his earnings would be $42 + $42, or $84.  So {b = 14 hours and c + 6 hours} is a solution.  As we continue to reduce the number of hours Chet works babysitting and correspondingly increase those he works landscaping, his earnings will go up, beyond $84.

Here's a table that summarizes this:

babysitting          landscaping    total amount

  hours                   hours               earned

      15                          5                      $60 (not acceptable)

       14                         6                       $84 (borderline acceptable)

       12                          8                       $36 + $42 = $78 (great)

        6                          14                       $116 (greater still)

         2                          18                     $132

          1                           19                      $134

          0                          20                      $140

Summary:  Chet can work anywhere from 0 to 14 hours babysitting and expect to earn $84 or more.

4 0
3 years ago
Find the degree of the monomial. 4x^7y^3 a. 3 b. 10 c. 7 d. 4
Mashcka [7]
The degree of a monomial is the sum of its exponents
4x^7y^3
exponents are 7 and 3
degree is : 7 + 3 = 10
7 0
3 years ago
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