Using a proportional relationship, we have that:
- a) The constant of proportionality is of 0.625, hence the equation is:
.
- b) The distance of two cities that are 5 miles apart is of 8 kilometers.
- c) When they are 200 kilometers apart, we have that the distance in miles is of
.
<h3>What is a proportional relationship?</h3>
- A <em>proportional relationship</em> is a function in which the <u>output variable is given by the input variable multiplied by a constant of proportionality</u>, that is:.
- In which k is the constant of proportionality.
Item a:
From the graph, when x = 8, y = 5, hence:
The constant of proportionality is of 0.625, hence the equation is: .
Item b:
From the graph, when y = 5, x = 8, hence:
- The distance of two cities that are 5 miles apart is of 8 kilometers.
Item c:
When they are 200 kilometers apart, we have that the distance in miles is of .
You can learn more about proportional relationship at brainly.com/question/13550871
Answer:
All you need to remember is the rules
Step-by-step explanation:
Let us remember
a to the m power x a to the nth power is = a to the m+n power. (add the exponents)
And
a to the m power ÷ a to the nth power is = a to the m-n power. (subtract the exponents) So
14 to the -4 power x 14 to the 7 power= 14 to the -4+7 which is equal to 14 to the 3rd power
Cross multiply:-
3(b - 2) = (2b - 5)(b + 2)
3b - 6 = 2b^2 + 4b - 5b - 10
2b^2 - 4b - 4 = 0
b^2 - 2b - 2 = 0
b = 2.73, -0.73 Answer
For a smoothing constant of 0.2
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 55.6 55.48 52.18 50.15 52.72 52.97 53.38 54.90
Forecast error - -12 -.6 -16.48 – 10.12 12.85 1.28 2.03 7.62 -2.9
The mean square error is 84.12
The mean forecast for period 11 is 54.38
For a smoothing constant of 0.8
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 48.40 53.68 41.94 41.99 58.80 54.96 54.99 59.80
Forecast error - -12 6.60 -14.68 0.06 21.01 -4.80 0.04 6.01 -7.80The mean square error is 107.17
The mean forecast for period 11 is 53.56
Based on the MSE, smoothing constant of .2 offers a better model since the mean forecast is much better compared to the 53.56 of the smoothing constant of 0.8.
Answer:
1/2
Step-by-step explanation:
