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stiks02 [169]
3 years ago
11

Approximate the value of square root 44 to The nearest hundredth

Mathematics
2 answers:
sergiy2304 [10]3 years ago
6 0

Answer:

6.63324958071

Step-by-step explanation:

gayaneshka [121]3 years ago
3 0

Answer:

the square root of 44 is 6.633

Step-by-step explanation:

sqrt(44) = 2(3.3+1/60) = 6.6+1/30 = 6.6333, actually accurate almost to the nearest 1/10000. For those who need help with rounding to the nearest hundredth (0.01), we drop digits AFTER the 2nd decimal, namely.

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The GCF would be : 4x^4
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The measures of the angles of a triangle are shown in the figure below. Solve for x.
MissTica

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Step-by-step explanation:

A triangle is 180 degrees.

115+40=165

180-165=25 degrees

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A tree in Kevin's backyard is 5/8 meters tall. It has been growing for 1 2/5 years. What is the unit rate in meters per year? No
irga5000 [103]

Answer:

o.4464287142 or 0.4

Step-by-step explanation:

The tree is 5/8 meters tall and that's in 1 2/5 years so you would divide them and you get .4464287142

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Horizontal and parallel lines c and d are cut by transversal p. At the intersection of lines c and p, the uppercase left angle i
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the answer is the option C

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Step-by-step explanation:

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3 years ago
Please Help !!Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will
VikaD [51]

Answer:

Albert = $2159.07; Marie = $2244.99; Hans = $2188.35; Max = $2147.40

Marie is $10 000 richer

Step-by-step explanation:

Albert

(a) $1000 at 1.2 % compounded monthly

A = P\left(1 + \dfrac{r}{n}\right)^{nt}

A = 1000(1 + 0.001)¹²⁰ = $1127.43

(b) $500 losing 2%

0.98 × 500 = $490

(c) $500 compounded continuously at 0.8%

\begin{array}{rcl}A & = & Pe^{rt}\\& = & 500e^{0.008 \times 10}\\& = &\mathbf{\$541.64}\\\end{array}\\

(d) Balance

Total = 1127.43 + 490.00+ 541.64 = $2159.07

Marie

(a) 1500 at 1.4 % compounded quarterly

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

(b) $500 gaining 4 %

1.04 × 500 = $520.00

(c) Balance

Total = 1724.99 + 520.00 = $2244.99

Hans

$2000 compounded continuously at 0.9 %

\begin{array}{rcl}A& = &2000e^{0.009 \times 10}\\& = &\mathbf{\$2188.35}\\\end{array}\\

Max

(a) $1000 decreasing exponentially at 0.5 % annually

A = 1000(1 - 0.005)¹⁰= $951.11

(b) $1000 at 1.8 % compounded biannually

A = 1000(1 + 0.009)²⁰ = $1196.29

(c) Balance

Total = 951.11 + 1196.29 = $2147.40

Marie is $ 10 000 richer at the end of the competition.

7 0
4 years ago
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