Question

Find the angle between the given vectors to the nearest tenth of a degree.

Answer 1

The question ask to find the angle between the given vector to the nearest tenth of a degree and base on the value or the coordinates of each vector, the possible value of the angle base on the said vectors is 1.8 degree. I hope you are satisfied with my answer and feel free to ask for more 

Answer 2

Answer: Hence, the angle between the given vectors is 1.8°.

Step-by-step explanation:

Since we have given that

$\vec{u}=-5\hat{i}-4\hat{j}\\\vec{v}=-4\hat{i}-3\hat{j}$

We need to find the angle between the given vectors:

$\cos\theta=\dfrac{\vec{u}.\vec{v}}{\mid\vec{u}\mid.\mid \vec{v}\mid}\\\\\cos \theta=\dfrac{(-5\hat{i}-4\hat{j}).-4\hat{i}-3\hat{j}}{\sqrt{(-5)^2+(-4)^2}\sqrt{(-4)^2+(-3)^2}}\\\\\cos \theta=\dfrac{20+12}{\sqrt{41}\sqrt{25}}\\\\\cos \theta=\dfrac{32}{5\sqrt{41}}\\\\\theta=\cos^{-1}(0.99)\\\\\theta=1.78^\circ$

Hence, the angle between the given vectors is 1.8°.