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4 years ago

Suppose

1 answer:

6 0

F(3) = t4(3) = 2

The value of the function at the point of expansion is the first (constant) term of the Taylor series.

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What is the radius of a circle with a area of 112 square inches

Ugo [173]

Answer:

$\displaystyle 5,9708213214...\:in.$

Step-by-step explanation:

$\displaystyle {\pi}r^2 = A \\ \\ \frac{{\pi}r^2}{\pi} = \frac{112}{\pi} \hookrightarrow \sqrt{35,650707253...} = \sqrt{r^2} \\ \\ \boxed{5,9708213214... = r}$

I am joyous to assist you at any time.

5 0

2 years ago

28 dollar,, and U WANT TO get half dollar in coins. What's the answer

rjkz [21]

28 x 2 = 56 half dollar coins

6 0

3 years ago

Read 2 more answers

Can someone please help me

Misha Larkins [42]

Try 9cm but I’m not quite sure please reply if it’s wrong or right

6 0

3 years ago

Read 2 more answers

Jason deposited $18 000 in a bank that offers an interest rate of 5% per annum compounded

8_murik_8 [283]

Answer:

$1995.97.

Step-by-step explanation:

Amount in bank after 20 days =

18000(1 + 0.05/365)^20

= $18049.38

So H = 18049.38 - 16093.41

= $1995.97.

3 0

2 years ago

DATA ANALYSIS AND STATISTICSProbabilities involving two rolls of a dieAn ordinary (falr) die is a cube with the numbers 1 throug

Zepler [3.9K]

Solution

The table below is the required sample space of the to fair die

From the above table

The sample space contain 36 outcomes

Event A: The sum is greater than 9

we will look at the table and count all the elements that are greater than 9

There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)

The probability for event A will be

$\begin{gathered} p(A)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(A)=\frac{6}{36} \\ p(A)=\frac{1}{6} \end{gathered}$

P(A) = 1/6

Event B: The sum is an even number.

We will look at the table and count the number of elements that are even

There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)

The probability for event B will be

$\begin{gathered} p(B)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(B)=\frac{18}{36} \\ p(B)=\frac{1}{2} \end{gathered}$

p(B) = 1/2

5 0

1 year ago