Suppose

1 answer:

6 0

F(3) = t4(3) = 2

The value of the function at the point of expansion is the first (constant) term of the Taylor series.

You might be interested in

What is the equation of the lines that passes through the points (-2, -3) and (4, -5)?

antoniya [11.8K]

Since all the options are in the slope intercept form, we find the equation using the formula,

$y = mx + c$
We can find m, the slope using the formula,

$m = \frac{ change \: in \: y }{change \: in \: x}$
$m = \frac{ - 5 - - 3}{4 - - 2}$
$m = \frac{ - 2}{6} = - \frac{1}{3}$

On substitution,

$y = - \frac{ 1}{3} x + c$

We use any of the points, say (-2,-3) to determine the value of c.

$- 3 = - \frac{1}{3} ( - 2) + c$
$c = - \frac{11}{3}$

The equation is therefore,

$y = - \frac{1}{3} x - \frac{11}{3}$

The correct answer is D.

6 0

2 years ago

Rewrite using only positive exponents. <br><br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3a%20%5E%7B%20-%201%7D%20b%

Komok [63]

That would be a / 3b^2

(re call that 1 /a^-1 = a)

6 0

3 years ago

An architect builds a model of a park in the shape of a rectangle. The model is 40.64 centimeters long and 66.04 centimeters wid

Nadusha1986 [10]

Answer:

8.3

Step-by-step explanation:

hopeee this helpss outt !!

3 0

2 years ago

Read 2 more answers

If X = 7 units, Y = 4 units, Z = 18 units, and h = 7 units, what is the surface area of the triangular prism shown above?

nata0808 [166]

Answer:

Step-by-step explanation:

3 0

2 years ago

HURRY PLSSSSSSS!!!!!

Tom [10]

Answer:

BRUH I DONT KNOW

Step-by-s

4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) DO ALL OF THAT TO FIND THE ANSWER

5 0

3 years ago

Read 2 more answers